C＃，WPF - > GUI不應該，而在BackgroundWorker的

Question

更新凍結這是迄今爲止我的項目：

private void test() 
    { 
     var rows = GetDataGridRows(dgVarConfig); 

     Dictionary<TextBlock, String> dic = new Dictionary<TextBlock, string>(); 
     foreach (DataGridRow r in rows) 
     { 
      TextBlock tb = cMatchEx.GetCellContent(r) as TextBlock; 
      dic.Add(tb, tb.Text); 
     } 

     if (!syntaxWorker.IsBusy) 
      syntaxWorker.RunWorkerAsync(dic); 
    } 



    private void syntaxWorker_DoWork(object sender, DoWorkEventArgs e) 
    { 
     if (e.Argument == null) 
      Thread.Sleep(100); 
     else 
     { 
      Dictionary<TextBlock, String> dic = (Dictionary<TextBlock, String>)e.Argument; 

      foreach (KeyValuePair<TextBlock, String> kvp in dic) 
      { 

       kvp.Key.Dispatcher.BeginInvoke(new Action(() => 
       { 
        kvp.Key.Inlines.Clear(); 
        Syntax.Highlight(kvp.Value).ForEach(x => kvp.Key.Inlines.Add(x)); 
       })); 
      } 

     } 
    } 

Syntax.Highlight：

public static class Syntax 
{ 
    static Regex subFormula = new Regex(@"\w+\(\)"); 
    static Regex sapFormula = new Regex(@"\w+\(([^)]+)\)"); 
    static Regex strings = new Regex(@"\'[^']+\'"); 
    static Regex numerals = new Regex(@"\b[0-9\.]+\b"); 
    static Regex characteristic = new Regex(@"(?:)?\w+(?:)?"); 
    static Regex andOr = new Regex(@"(and)|(AND)|(or)|(OR)"); 
    static Regex not = new Regex(@"(not)|(NOT)"); 

    private static Brush[] colorArray; 

    public static List<Run> Highlight(String input) 
    { 


     colorArray = new Brush[input.Length]; 

     for (int i = 0; i < input.Length; i++) 
      colorArray[i] = Brushes.Black; 

     //Reihenfolge beibehalten!! 
     assignColor(Brushes.Blue, characteristic.Matches(input)); 
     assignColor(Brushes.Black, andOr.Matches(input)); 
     assignColor(Brushes.Black, numerals.Matches(input)); 
     assignColor(Brushes.Orange, strings.Matches(input)); 
     assignColor(Brushes.DeepPink, subFormula.Matches(input)); 
     assignColor(Brushes.Green, sapFormula.Matches(input)); 
     assignColor(Brushes.Green, not.Matches(input)); 


     int index = 0; 

     List<Run> runList = new List<Run>(); 

     foreach (Char character in input) 
     { 

      runList.Add(new Run(character.ToString()) { Foreground = colorArray[index] }); 
      index++; 
     } 


     colorArray = null; 
     return runList; 
    } 

    public static void Check(TextBlock textBlock) 
    { 

    } 


    private static void assignColor(Brush brush, MatchCollection matchCollection) 
    { 
     foreach (Match match in matchCollection) 
     { 
      int start = match.Index; 
      int end = start + match.Length; 

      for (int i = start; i < end; i++) 
      { 
       colorArray[i] = brush; 
      } 
     } 
    } 
} 

有了這個代碼，以獲取有關GUI凍結2秒。有什麼辦法可以逐步建立GUI並避免任何凍結？ 它沒有問題，看它如何建立，只是凍結是一個問題。

希望有人知道如何解決這個問題。

Answer 1

你可以像這樣的調用外部移動工作的一個很好的部分：

一個小小的警告：我不完全相信你如何retreive文本框的文本。您可能需要爲此單獨調用（請參閱代碼中的註釋）

public class RunInfo 
{ 
    public string Content { get; set;} 
    public Color foreground { get; set; } 
    public RunInfo(string content) 
    { 
     Content = content; 
    } 

    public Run AsRun() 
    { 
     return new Run(Content){ Foreground = foreground }; 
    } 

} 



public static class Syntax 
{ 
    static Regex subFormula = new Regex(@"\w+\(\)"); 
    static Regex sapFormula = new Regex(@"\w+\(([^)]+)\)"); 
    static Regex strings = new Regex(@"\'[^']+\'"); 
    static Regex numerals = new Regex(@"\b[0-9\.]+\b"); 
    static Regex characteristic = new Regex(@"(?:)?\w+(?:)?"); 
    static Regex andOr = new Regex(@"(and)|(AND)|(or)|(OR)"); 
    static Regex not = new Regex(@"(not)|(NOT)"); 

    private static Brush[] colorArray; 

    public static List<RunInfo> Highlight(String input) 
    { 


     colorArray = new Brush[input.Length]; 

     for (int i = 0; i < input.Length; i++) 
      colorArray[i] = Brushes.Black; 

     //Reihenfolge beibehalten!! 
     assignColor(Brushes.Blue, characteristic.Matches(input)); 
     assignColor(Brushes.Black, andOr.Matches(input)); 
     assignColor(Brushes.Black, numerals.Matches(input)); 
     assignColor(Brushes.Orange, strings.Matches(input)); 
     assignColor(Brushes.DeepPink, subFormula.Matches(input)); 
     assignColor(Brushes.Green, sapFormula.Matches(input)); 
     assignColor(Brushes.Green, not.Matches(input)); 


     int index = 0; 

     List<Run> runList = new List<Run>(); 

     foreach (Char character in input) 
     { 

      runList.Add(new RunInfo(character.ToString()) { Foreground = colorArray[index] }); 
      index++; 
     } 


     colorArray = null; 
     return runList; 
    } 

    public static void Check(TextBlock textBlock) 
    { 

    } 


    private static void assignColor(Brush brush, MatchCollection matchCollection) 
    { 
     foreach (Match match in matchCollection) 
     { 
      int start = match.Index; 
      int end = start + match.Length; 

      for (int i = start; i < end; i++) 
      { 
       colorArray[i] = brush; 
      } 
     } 
    } 
} 




private void syntaxWorker_DoWork(object sender, DoWorkEventArgs e) 
{ 
    if (e.Argument == null) 
     Thread.Sleep(100); 
    else 
    { 
     Dictionary<TextBlock, String> dic = (Dictionary<TextBlock, String>)e.Argument; 

     foreach (KeyValuePair<TextBlock, String> kvp in dic) 
     { 
      //i am unsure if this line will work. if it does not, you might need to do a separate dispatcher invoke in order to retreive the text from the textbox. 
      List<RunInfo> runinfoObjects = Syntax.Highlight(kvp.Value); 
      kvp.Key.Dispatcher.BeginInvoke(new Action(() => 
      { 
       kvp.Key.Inlines.Clear(); 
       //we'd run into problems here, since wpf won't allow us to add elements created in a background thread. since we now make the Run object inside the invoke, we should be fine. 
       runinfoObjects.ForEach(x => kvp.Key.Inlines.Add(x.AsRun())); 
      })); 
     } 
    } 
}