在同一個標​​簽上的三個UIButton之間切換selectedState

Question

我在同一個標​​簽上有3個UIButton。

問題： 當我點擊按鈕1，按鈕2和BUTTON3他們都得到了選擇;然而，我想要的是當我選擇（例如）button2，其他按鈕被取消選中（就像html上的單選按鈕）。 關於如何解決此問題的任何想法？

這裏是我的代碼：

- (IBAction)button1:(UIButton *)sender { 
    sender.selected = !sender.selected; 
} 
- (IBAction)button2:(UIButton *)sender { 
sender.selected = !sender.selected; 
} 
- (IBAction)button3:(UIButton *)sender { 
sender.selected = !sender.selected; 
} 

Answer 1

有幾個直接的解決方案。也許他們是不是最佳的，但你可以使用它們：

解決方案一：

與相應的屬性將您的按鈕：

@property (weak, nonatomic) IBOutlet UIButton *button1; 
@property (weak, nonatomic) IBOutlet UIButton *button2; 
@property (weak, nonatomic) IBOutlet UIButton *button3; 

在每個動作變化選擇屬性各按鈕：

- (IBAction)button1Clicked:(UIButton *)sender { 
    _button1.selected = YES; 
    _button2.selected = NO; 
    _button3.selected = NO; 
} 

Se COND解決方案：

添加所有按鈕的NSArray：

NSArray *buttonsArray = [[NSArray alloc] initWithObjects: button1, button2, button3, nil]; 

然後用戶可以鏈接所有的按鈕與一個動作：

- (IBAction)buttonClicked:(UIButton *)sender { 
    for (UIButton *btn in _buttonsArray) { 
     if (btn == sender) 
      btn.selected = YES; 
     else 
      btn.selected = NO; 
    } 
} 

不要忘了讓所有的NSArray的訪問例如通過創建相應的屬性：

@property (weak, nonatomic) NSArray *buttonsArray; 

解決方案三：

您可以更改標籤屬性爲每個按鈕（通過界面生成器或代碼）：

_button1.tag = 1; 
_button2.tag = 2; 
_button3.tag = 3; 

然後，所有的按鈕與一個動作（就像在前面的例子）鏈接：

- (IBAction)buttonClicked:(UIButton *)sender { 
    if (sender.tag == 1) { 
     _button1.selected = YES; 
     _button2.selected = NO; 
     _button3.selected = NO; 
    } else if (sender.tag == 2) { 
     _button1.selected = NO; 
     _button2.selected = YES; 
     _button3.selected = NO; 
    } else if (sender.tag == 3) { 
     _button1.selected = NO; 
     _button2.selected = NO; 
     _button3.selected = YES; 
    } 
} 

第四溶液：（由@ velmurugan-S）

使用一個操作所有按鈕，並設置其默認狀態，以選擇= NO：

- (IBAction)buttonClicked:(UIButton *)sender { 
    _button1.selected = NO; 
    _button2.selected = NO; 
    _button3.selected = NO; 

    sender.selected = YES; 
} 

摘要：

我建議你使用第二個解決方案是最優的一個。

Answer 2

你不得不改變選擇的沙爹爲您選擇了一個按鈕，您需要更改其他按鈕狀態了。

Answer 3

- (IBAction)button1:(UIButton *)sender { 
    btn1.selected = YES; 
    btn2.selected = NO; 
    btn3.selected = NO; 

} 
- (IBAction)button2:(UIButton *)sender { 

    btn1.selected = NO; 
    btn2.selected = YES; 
    btn3.selected = NO; 
} 
- (IBAction)button3:(UIButton *)sender { 
    btn1.selected = NO; 
    btn2.selected = NO; 
    btn3.selected = YES; 
} 

Answer 4

你可以做的是在接口部分連接按鈕1，按鈕2，按鈕3，以相同的button123給他們適當的標籤

- (IBAction)button123:(UIButton *)sender;

在下面的代碼

- (IBAction)button123:(UIButton *)sender { 

if (sender.tag == 111) 
{ 
    sender.selected = !sender.selected; 

    if (sender.selected) 
    { 
     self.button2.selected = NO; 
     self.button3.selected = NO; 


    } 

} 
else if (sender.tag == 222) 
{ 
    sender.selected = !sender.selected; 

    if (sender.selected) 
    { 
     self.button1.selected = NO; 
     self.button3.selected = NO; 

    } 


} 
else if (sender.tag == 333) 
{ 
    sender.selected = !sender.selected; 

    if (sender.selected) 
    { 
     self.button1.selected = NO; 
     self.button2.selected = NO; 

    } 

}