我有一個JavaScript和HTML代碼:使用jQuery建立表格行從Ajax響應(不與靜態JSON數據)
<script type="text/javascript" src="jquery-1.11.3.js"> </script>
<script type="text/javascript">
$(document).ready(function()
{
$.ajax({
url: "getjson.php",
type: "POST",
success: function (response)
{
console.log(response);
var trHTML = '';
$.each(response, function (i, item)
{
trHTML +=
'<tr><td>' + item.id +
'</td><td>' + item.konu +
'</td><td>' + item.aciklama +
'</td><td>' + item.giris_tarih +
'</td><td>' + item.degistirilme_tarih +
'</td><td>' + item.ad_soyad +
'</td><td>' + item.email +
'</td></tr>';
});
$('#records_table').append(trHTML);
}
});
});
</script>
<table id="records_table" border='1'>
<tr>
<th align="center" width="50">Id</th>
<th align="center" width="100">Konu</th>
<th align="center" width="100">Aciklama</th>
<th align="center" width="100">Giris Tarih</th>
<th align="center" width="150">Degistirilme Tarih</th>
<th align="center" width="100">Ad Soyad</th>
<th align="center" width="100">Email</th>
</tr>
</table>
此代碼不能正常工作。它只創建第一行,但不會從getjson.php獲得json響應。 當我使用jsfiddle中的靜態json數據,像這樣https://jsfiddle.net/tqyn3/761/,它就像我想的那樣工作。但我想從getjson.php獲取數據。 如何將其轉換爲動態?
更新: 在調試器控制檯它寫在上面:
showjson.php:12
{"kullanicilar":[{"id":"6","konu":"blood angels","aciklama":"primarch","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"singuinius","email":"warhammer"},{"id":"7","konu":"emperors children","aciklama":"daemon primarch","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"fulgrim","email":"warhammer"},{"id":"8","konu":"night lords","aciklama":"primarch","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"konrad curze","email":"warhammer"},{"id":"9","konu":"grey knights","aciklama":"grand master","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"grand master","email":"warhammer40k"},{"id":"10","konu":"dark angels","aciklama":"primarch","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"lion el jonson","email":"warhammer40k"}]}
,並在下面寫有紅色文字:
jquery-1.11.3.js:577 Uncaught TypeError: Cannot use 'in' operator to search for 'length' in
{"kullanicilar":[{"id":"6","konu":"blood angels","aciklama":"primarch","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"singuinius","email":"warhammer"},{"id":"7","konu":"emperors children","aciklama":"daemon primarch","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"fulgrim","email":"warhammer"},{"id":"8","konu":"night lords","aciklama":"primarch","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"konrad curze","email":"warhammer"},{"id":"9","konu":"grey knights","aciklama":"grand master","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"grand master","email":"warhammer40k"},{"id":"10","konu":"dark angels","aciklama":"primarch","giris_tarih":"0000-00-00","degistirilme_tarih":"0000-00-00","ad_soyad":"lion el jonson","email":"warhammer40k"}]}
檢查什麼是服務器(執行console.log(響應)) – Daimos
返回什麼是'getjson.php'?也許'getjson'不返回JSON有效 – ashkufaraz
getjson.php是從獲取數據的另一個文件mysql並將其解析爲json。當我只調用getjsonphp時,它返回的數據沒有任何問題。在我的jsfiddle鏈接中,它從getjson.php返回的數據 – gunes