Python 3 - 遍歷整個語料庫並記錄它的計數

Question

我有一個語料庫，它是一個元組列表，包含一個單詞和一個POS標籤的元組。我現在的問題是給出語料庫中存在的每個單詞和每個POS標籤，遍歷該語料庫並記錄每個單詞和標籤組合存在於語料庫中的時間量。如果單詞和標籤組合不會在語料庫存在使得計數爲0

 possible_tags = ['Verb','Noun','Det'] 

    possible_words = ['Merger', 'proposed', 'Wards', 'protected', 'A'] 

    corpus = [('Merger', 'Noun'), ('proposed', 'Verb'), ('Wards', 'Noun'), ('protected', 'Verb'), ('A', 'Det'), ('Merger','Noun')] 

    output = {'Merger_Noun':2, 'Merger_Verb':0, 'Merger_Det':0, 'proposed_Noun':0, 'proposed_Verb':1, 'proposed_Det':0, ....... } 

Answer 1

想盡轉換爲一個字典，使其更容易。

possible_tags = ['Verb','Noun','Det'] 

possible_words = ['Merger', 'proposed', 'Wards', 'protected', 'A'] 

corpus = [('Merger', 'Noun'), ('proposed', 'Verb'), ('Wards', 'Noun'), ('protected', 'Verb'), ('A', 'Det'), ('Merger','Noun')] 

#Initialize output to empty dictionary 
output = {} 

//dictionary initialization. 

for each_word in possible_words: 
    for each_tag in possible_tags: 
     key = each_word + "_" + each_tag 
     output[key] = 0 


#iterate through corpus 
for each in corpus: 
    #extract each tuple, and update dictionary with keys as string and count as integer 
    output[each[0] +"_"+each[1]] += 1