我正在尋找每個ID每天兩個表之間的最大差異。我有一個MySQL數據庫SQL子查詢試圖獲得兩個表中同一列的最大差異
insert into test.foo values ('2010-01-10', 1, 10);
insert into test.foo values ('2010-01-10', 1, 5);
insert into test.foo values ('2010-01-10', 2, 10);
insert into test.foo values ('2010-01-10', 2, 10);
insert into test.foo values ('2010-01-10', 3, 15);
insert into test.foo values ('2010-01-10', 3, 15);
insert into test.foo values ('2010-01-11', 1, 5);
insert into test.foo values ('2010-01-11', 1, 5);
insert into test.foo values ('2010-01-11', 2, 5);
insert into test.foo values ('2010-01-11', 2, 5);
insert into test.foo values ('2010-01-11', 3, 5);
insert into test.foo values ('2010-01-11', 3, 5);
insert into test.bar values ('2010-01-10', 1, 5);
insert into test.bar values ('2010-01-10', 1, 5);
insert into test.bar values ('2010-01-10', 2, 5);
insert into test.bar values ('2010-01-10', 2, 5);
insert into test.bar values ('2010-01-10', 3, 5);
insert into test.bar values ('2010-01-10', 3, 5);
insert into test.bar values ('2010-01-11', 1, 10);
insert into test.bar values ('2010-01-11', 1, 10);
insert into test.bar values ('2010-01-11', 2, 5);
insert into test.bar values ('2010-01-11', 2, 5);
insert into test.bar values ('2010-01-11', 3, 5);
insert into test.bar values ('2010-01-11', 3, 5);
在這裏,下面的數據是我的查詢:
SELECT t1.`date`, t1.id, t1.sums, t2.sums, max(t1.sums - t2.sums) FROM
(select `date`, id, sum(val) sums
from test.foo
group by `date`, id) as t1,
(select `date`, id, sum(val) sums
from test.bar
group by `date`, id) as t2
WHERE t1.`date` = t2.`date` AND t1.id = t2.id
group by t1.`date`
我得到這個結果:
+---------------------+----+------+------+------------------------+
| date | id | sums | sums | max(t1.sums - t2.sums) |
+---------------------+----+------+------+------------------------+
| 2010-01-10 00:00:00 | 1 | 15 | 10 | 20 |
| 2010-01-11 00:00:00 | 1 | 10 | 20 | 0 |
+---------------------+----+------+------+------------------------+
2 rows in set (0.00 sec)
我想收到此結果: 我得到這個結果:
+---------------------+----+------+------+------------------------+
| date | id | sums | sums | max(t1.sums - t2.sums) |
+---------------------+----+------+------+------------------------+
| 2010-01-10 00:00:00 | 1 | 15 | 10 | 20 |
| 2010-01-11 00:00:00 | 2 | 10 | 10 | 0 | <-----
+---------------------+----+------+------+------------------------+
任何人都可以幫助我嗎?我希望得到最大的區別,然後是與之相伴的路線。這個查詢給了我正確的區別,但不是與它一起使用的id和總數。一位同事也建議按ID分組,但正如我所認爲的那樣,只是將結果放平,並且每個ID都列出來,而不是一天中具有最大差異的一個ID。
感謝很多提前
什麼數據庫和版本? – RedFilter 2010-01-12 14:38:07
不應該也是你的結果? – RedFilter 2010-01-12 14:39:37
mysql Ver 14.14 Distrib 5.1.39,用於Win32(ia32) – 2010-01-12 14:40:50