匹配一個字符串與數組

Question

我正在循環一個數組，並再次循環這些值，以匹配它與字符串，如果整個給定的字符串匹配將數組的整個元素，他們我應該打印該字符串，但它不工作

public class find 
{ 
string[] inputs = {"Third Street Promenade, 1220 3rd St ,Santa Monica, CA 90401","Hi there should"}; 
string store_tran1 = "1220 3rd St ,Santa Monica, CA 90401" 

foreach(var store in stores){ 

         List<string> outputs = new List<string>(); 
foreach (var input in inputs) 
         { 
          outputs.AddRange((new String(input.ToCharArray() 
           .Where(c => Char.IsLetterOrDigit(c) || c == ' ') 
           .ToArray()).Split(' '))); 
         } 
foreach (var output in outputs) 
          { 



           //string sto = store.ToString(); 
           //Console.Write (output+"\n"); 
           bool store_match_check_1 = Regex.IsMatch (store_tran1, @""+Regex.Escape (output)+"", RegexOptions.IgnoreCase); 
           if (store_match_check_1 == true) { 
            //string store_match_check1 = store_match_check_1.Groups [1].Value; 

            res = true; 

           } else { 
            store_array_check.Add ("one"); 
            res = false; 
           } 


          } 


} 
} 

預期輸出：

Third Street Promenade, 1220 3rd St ,Santa Monica, CA 9040 

我怎麼能得到這個沃金

Answer 1

爲什麼不

var inputs = new[] { "Third Street Promenade, 1220 3rd St ,Santa Monica, CA 90401", "Hi there should" }; 
var store_tran1 = "1220 3rd St ,Santa Monica, CA 90401"; 
foreach (var input in inputs) 
{ 
    if (input.Contains(store_tran1)) 
    { 
     Console.WriteLine(input); 
    } 
} 

（如果你需要，你可以隨時通過調用ToLower()或致電Trim()刪除空格忽略大小寫）

Answer 2

你的正則表達式從輸入字符串刪除逗號，所以你不會得到任何比賽。

如果你真的要刪除所有非字母數字字符+逗號，你可以使用LINQ像這樣：

var inputs = new[] {"Third Street Promenade, 1220 3rd St ,Santa Monica, CA 90401","Hi there should"}; 
var store_tran1 = "1220 3rd St ,Santa Monica, CA 90401"; 
inputs.Select(s => Regex.Replace(s, @"^\s*|[^\w\s,]+|\s*$", "")) 
     .Where(s => s.Contains(store_tran1)) 
     .ToList() 
     .ForEach(Console.WriteLine); 

正則表達式也將受益於輸入字符串的開頭和結尾修剪空白。

C# demo。