Java玩家板初始化

我是Java新手，現在我正在解決這個問題。我得到了一個遊戲板（AxA），所以它的二維數組和每個盒子裏都需要有關於行和列的信息，而且還有大約8個對象，圍繞着這個盒子。這是現在它做Java玩家板初始化

for (int x = 0; x < size; x++) { 
     for (int y = 0; y < size; y++) { 
      Field neighbours[] = new Field[8]; 

      neighbours[0] = x-1 >= 0 && x-1 < 8 ? this.playBoard[x-1][y] : null; 
      neighbours[1] = x-1 >= 0 && x-1 < 8 && y+1 >= 0 && y+1 < 8 ? this.playBoard[x-1][y+1] : null; 
      neighbours[2] = y+1 >= 0 && y+1 < 8 ? this.playBoard[x][y+1] : null; 
      neighbours[3] = x+1 >= 0 && x+1 < 8 && y+1 >= 0 && y+1 < 8 ? this.playBoard[x+1][y+1] : null; 
      neighbours[4] = x+1 >= 0 && x+1 < 8 ? this.playBoard[x+1][y] : null; 
      neighbours[5] = x+1 >= 0 && x+1 < 8 && y-1 >= 0 && y-1 < 8 ? this.playBoard[x+1][y-1] : null; 
      neighbours[6] = y-1 >= 0 && y-1 < 8 ? this.playBoard[x][y-1] : null; 
      neighbours[7] = x-1 >= 0 && x-1 < 8 && y-1 >= 0 && y-1 < 8 ? this.playBoard[x-1][y-1] : null; 

      System.out.println("X: "+x+", Y: "+y); 
      for(int i = 0; i < neighbours.length; i++) 
       System.out.println(" "+neighbours[i]); 

      this.playBoard[x][y] = new FieldClass(x, y, neighbours); 
     } 
    }

唯一問題是，如果我試圖挽救一些箱子作爲鄰居，我還沒有遍歷，所以沒有對象，我得到空，這是合乎邏輯的，因爲這個對象是沒有初始化，所以我不能在那裏。我怎麼能這樣做，它會工作的財產？

來源

2016-03-04 Nikolas Kantor

分兩步進行 - 初始化電路板，然後遍歷它以找到鄰居。 – TDG

for (int x = 0; x < size; x++) { 
    for (int y = 0; y < size; y++) { 
     this.playBoard[x][y] = new FieldClass(x, y); 
    } 
} 

for (int x = 0; x < size; x++) { 
    for (int y = 0; y < size; y++) { 
     Field neighbours[] = new Field[8]; 

     neighbours[0] = x-1 >= 0 && x-1 < 8 ? this.playBoard[x-1][y] : null; 
     neighbours[1] = x-1 >= 0 && x-1 < 8 && y+1 >= 0 && y+1 < 8 ? this.playBoard[x-1][y+1] : null; 
     neighbours[2] = y+1 >= 0 && y+1 < 8 ? this.playBoard[x][y+1] : null; 
     neighbours[3] = x+1 >= 0 && x+1 < 8 && y+1 >= 0 && y+1 < 8 ? this.playBoard[x+1][y+1] : null; 
     neighbours[4] = x+1 >= 0 && x+1 < 8 ? this.playBoard[x+1][y] : null; 
     neighbours[5] = x+1 >= 0 && x+1 < 8 && y-1 >= 0 && y-1 < 8 ? this.playBoard[x+1][y-1] : null; 
     neighbours[6] = y-1 >= 0 && y-1 < 8 ? this.playBoard[x][y-1] : null; 
     neighbours[7] = x-1 >= 0 && x-1 < 8 && y-1 >= 0 && y-1 < 8 ? this.playBoard[x-1][y-1] : null; 

     System.out.println("X: "+x+", Y: "+y); 
     for(int i = 0; i < neighbours.length; i++) 
      System.out.println(" "+neighbours[i]); 

     this.playBoard[x][y].setNeighbours(neighbours)); 
    } 
}

來源

2016-03-04 11:56:56

所以，當你添加[X，Y]作爲鄰居[U，V]請確保您添加[U，V]爲[X，Y]的鄰居

你將不得不拆分儘管如此，你的三元運算符轉換爲傳統的if語句。

來源

2016-03-04 11:53:52

Java玩家板初始化

回答

相關問題