Java-撲克玩家

Question

我有一個任務來創建一個撲克遊戲，詢問有多少人在玩（1-7），以及他們是否想玩5張牌螺柱或7張。這些沒有投注圖等等。簡單的一方面看你有什麼遊戲。我需要讓方法Questions爲gameType和numPlayers都返回一個值。 5張牌組和7張牌組取決於從gameType變量返回的值。我不知道如何做到這一點......任何想法？

我也必須以某種方式將多個玩家集成到甲板中。

import java.util.Scanner; 

public class pokerGame { 

    public static void main(String[] args) { 
     Questions(); 
     if (Questions == 5){ 
      Deck5();} 
      else{ 
       Deck7();} 
    } 

     public static int Questions() { 
      int numPlayers, gameType; 
      Scanner sc = new Scanner(System.in); 
      System.out.print("How many people do we have playing poker today? " + "Enter a number between 1 and 7: \n"); 
      numPlayers = sc.nextInt(); 
      System.out.println("Are you playing 7 car stud or 5 card stud?"); 
      gameType = sc.nextInt(); 
      return gameType; 
     } 

public static String Deck5() { 
     int[] deck = new int[52]; 
     String[] suits = { "Spades", "Hearts", "Diamonds", "Clubs" }; 
     String[] ranks = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King" }; 
     // Initialize cards 
     for (int i = 0; i < deck.length; i++){ 
      deck[i] = i; 
      String suit = suits[deck[i]/13]; 
      String rank = ranks[deck[i] % 13]; 

     //show the deck in the original order 
     System.out.println(deck[i] + ": " + rank + " of " + suit + "\n"); 
     } 
     // Shuffle the cards 
     for (int i = 0; i < deck.length; i++) { 

      // Generate an index randomly 
      int index = (int) (Math.random() * deck.length); 
      int temp = deck[i]; 
      deck[i] = deck[index]; 
      deck[index] = temp; 
     } 

     // Display the 5 cards 
     for (int i = 0; i < 5; i++) { 
      String suit = suits[deck[i]/13]; 
      String rank = ranks[deck[i] % 13]; 
      System.out.println(rank + " of " + suit); 
     } 

    public static String Deck7(); 
     int[] deck = new int[52]; 
     String[] suits = { "Spades", "Hearts", "Diamonds", "Clubs" }; 
     String[] ranks = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King" }; 
     // Initialize cards 
     for (int i = 0; i < deck.length; i++) 
      deck[i] = i; 

     // Shuffle the cards 
     for (int i = 0; i < deck.length; i++) { 
      // Generate an index randomly 
      int index = (int) (Math.random() * deck.length); 
      int temp = deck[i]; 
      deck[i] = deck[index]; 
      deck[index] = temp; 
     } 

     // Display the 5 cards 
     for (int i = 0; i < 7; i++) { 
      String suit = suits[deck[i]/13]; 
      String rank = ranks[deck[i] % 13]; 
      System.out.println(rank + " of " + suit); 
     } 
    } 
} 

Answer 1

如果您遇到的問題是Questions類將如何返回兩個整數到您的主類，您將無法。如果你唯一的問題是找到一種方法來返回兩個整數，你可以用一個單獨的類爲那個有兩個int變量的玩家的數量和牌組大小。我不太瞭解你的代碼是如何工作的。你不會在主課堂中調用Deck5或Deck7課程。

編輯： 你可以完全擺脫問題類，只是將問題移到主類。這樣你就不用擔心返回任何東西。如果你真的需要問題類，那麼就像我之前說過的那樣，用變量numPlayers和gameType創建一個單獨的類「遊戲」，並將其返回給主類。

就玩家人數問題而言，我會將玩家數量作爲參數傳遞給您的套牌方法。然後在運行這一位代碼的套牌方法內創建for循環：

for (int i = 0; i < 7; i++) { 
     String suit = suits[deck[i]/13]; 
     String rank = ranks[deck[i] % 13]; 
     System.out.println(rank + " of " + suit);} 

每個玩家一次。

此外，您用於甲板的代碼效率不高。沒有必要洗牌。相反，當生成用戶卡時，只需在那裏生成一個隨機整數。