的Python HOWTO例外句柄<的urlopen錯誤[錯誤54]通過對等連接重置>

Question

我在Python腳本2.7擦傷網站每一分鐘，但有時也給出了錯誤：

的urlopen錯誤[錯誤54]連接由復位同行>

我如何處理異常？我想是這樣的：

from socket import error as SocketError 
import errno 

try: 
    response = urllib2.urlopen(request).read() 
except SocketError as e: 
    if e.errno != errno.ECONNRESET: 
     print "there is a time-out" 
    pass 
     print "There is no time-out, continue" 

Answer 1

您可以處理這樣的例外：

from socket import error as SocketError 
import errno  

try: 
    urllib2.urlopen(request).read() 
except SocketError, e: 
    errorcode = e[0] 
    if errorcode!=errno.ECONNREFUSED: 
     print "There is a time-out" 
     # Not the error we are looking for, re-raise 
     raise e 

您可以閱讀Error Code