2017-02-04 107 views
1

幫助。我怎麼能移動或從一個表中移動一行到另一個mysql表中?一旦我點擊「批准」,選定的行將轉移到數據庫中的另一個表格。請檢查我的代碼。謝謝!如何將一行從一個表移動到另一個表中的mysql?

message.php

<?php 


include('connect.php'); 
$result = mysqli_query($GLOBALS["___mysqli_ston"], "SELECT * FROM message"); 
while($row = mysqli_fetch_array($result)) 
{ 
    echo '<tr class="record">'; 
    echo '<td style="background-color: #F8F8F8 ;font-size: 13px; color: maroon; 
     font-weight: bold; border-left: 1px solid #C1DAD7;">'.$row['name'].'</td>'; 
    echo '<td><div style="font-size: 13px;" align="left">'.$row['address'].'</div></td>'; 
    echo '<td><div style="color:maroon; font-size: 13px;"align="left">Email:<br></div> 
     <div style="font-size: 13px;"align="left">'.$row['email'].'</div><br> 
     <div style="font-size: 13px; color:maroon;"align="left">Contact No.<br></div> 
     <div style="font-size: 13px;"align="left">'.$row['number'].'</div></td>'; 
    echo '<td><div style="font-size: 13px;"align="left">'.$row['services'].'</div></td>'; 
    echo '<td><div style="color:maroon; font-size: 13px;"align="left">Desired Date:<br></div> 
     <div style="font-size: 13px;"align="left">'.$row['shootdate'].'</div><br> 
     <div style="font-size: 13px; color:maroon;"align="left">Desired Time: <br></div> 
     <div style="font-size: 13px;"align="left">'.$row['shoottime'].'</div></td>'; 
    echo '<td><div style="font-size: 13px;"align="left">'.$row['place'].'</div></td>'; 
    echo '<td><div style="font-size: 13px;"align="left">'.$row['message'].'</div></td>'; 
    echo '<td><div align="center"> 
     <a href="acceptmessage.php" id="'.$row['message_id'].'" class="acceptbutton" 
      title="Click To Approve">Approve</a><br><br> 
     <a href="deletemessage.php" id="'.$row['message_id'].'" class="delbutton" 
      title="Click To Decline" style="color:red;">Decline</a></div></td>'; 
    echo '</tr>'; 
    } 
?> 

acceptmessage.php

<?php 
    include('../db.php'); 
    if($_GET['id']){ 
    $id = (isset($_GET['id']) ? $_GET['id'] : null); 
    $sql = "INSERT INTO accept (name, address, email, number, services, shootdate, shoottime, place) SELECT name, address, email, number, services, shootdate, shoottime, place FROM message WHERE message_id='$id'"; 
    mysqli_query($GLOBALS["___mysqli_ston"], $sql);} 
?> 
+2

你有錯誤? .. – scaisEdge

回答

1

如果列MESSAGE_ID是int我想你應該刪除$ ID的單引號是這樣的:

$sql = "INSERT INTO accept (name, address, email, number, services, shootdate, shoottime, place) SELECT name, address, email, number, services, shootdate, shoottime, place FROM message WHERE message_id=$id"; 

P.S.您應該在查詢中使用準備好的語句,而不是直接插入變量,這樣可以避免SQL注入。

事情是這樣的:

$sql = "INSERT INTO accept (name, address, email, number, services, shootdate, shoottime, place) SELECT name, address, email, number, services, shootdate, shoottime, place FROM message WHERE message_id=?"; 
$stmt = $connection->prepare($sql); 
$stmt->bindValue(1, $id); 
$stmt->execute(); 
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