我需要一個良好的MySQL查詢到從3代表接受信息

Question

我有這樣的功能：

function view_user_anunt($user) { 
    $query="SELECT * FROM `anunturi` 
      FULL OUTER JOIN tranzactie 
      ON anunturi.tranzactie = tranzactie.id_tranzactie WHERE `anunturi.user`=:code"; 

     $stmt = $this->dbh->prepare($query); 
     $stmt->bindParam(':code', $user, PDO::PARAM_INT); 
     $stmt->execute(); 
     foreach ($stmt->fetchAll(PDO::FETCH_ASSOC) as $result) 
     { 
      $view[]=" 
      <tr> 
      <td>".$result['id_anunt']."</td> 
      <td>".$result['den_tranzactie']."</td> 
      <td>".$result['den_proprietate']."</td> 
      <td><a href='#' id='vizualizare'>Select</a></td> 
      <td><a href='#' id='modificare'>Select</a></td> 
      </tr>"; 

     } 
    return $view; 


} 

和3個表：

anunturi

• id_anunt（INT）自動遞增
• tranzactie（int）
• 則提示（INT）
• 用戶（INT）

tranzactie

• id_tranzactie（int）的自動增量
• den_tranzactie VARCHAR

尖端

• id_proprietate（INT）自動遞增
• den_proprietate VARCHAR

我需要從anunturi每行一個很好的查詢或IDEEA得到事務名稱（den_tranzactie）和proprietate名den_proprietate其中anunturi.user = $用戶。

在此先感謝...

Answer 1

試試這個sql查詢

$query="SELECT t1.*, t2.*, t3.* 
     FROM table1 t1 
     LEFT JOIN table2 t2 ON t1.id = t2.foreightkey_id 
     LEFT JOIN table3 t3 ON t1.id = t3.foreightkey_id 
     WHERE t1.user=:code 
"; 

您可以使用INNER JOIN只接收行的女巫都表中的數據。例如

$query="SELECT t1.*, t2.*, t3.* 
      FROM table1 t1 
      INNER JOIN table2 t2 ON t1.id = t2.foreightkey_id 
      INNER JOIN table3 t3 ON t1.id = t3.foreightkey_id 
      WHERE t1.user=:code 
    "; 

，或者如果你想獲得從Table 1和Table您想連接，並從只有那種連接

$query="SELECT t1.*, t2.*, t3.* 
       FROM table1 t1 
       INNER JOIN table2 t2 ON t1.id = t2.foreightkey_id 
       LEFT JOIN table3 t3 ON t1.id = t3.foreightkey_id 
       WHERE t1.user=:code 
     "; 

Answer 2

是這樣的嗎？

' 
SELECT t.den_tranzactie, tip.den_proprietate 
FROM 
anunturi a 
JOIN tranzactie t ON a.tranzactie = t.id_tranzactie 
JOIN tip ON a.tip = tip.id_proprietate 
WHERE a.user =:code