窗體不顯示空記錄

我有一個相對簡單的PHP頁面，稱爲editcustomers與3列。我遇到的問題是表單將顯示數據庫中有記錄，並且字段將填充該信息。窗體不顯示空記錄

當不存在這樣的記錄時，甚至不顯示該表格，從而消除了插入記錄的可能性。

我的頁面佈局如下：

第1欄示出了包含客戶信息的形式，它允許進行編輯。
第2列允許訂購產品並顯示訂購了多少產品
第3列顯示迄今爲止支付的總額以及欠款總額。

這個頁面的代碼，我現在：

<html> 
<?php 
$id = $_GET['id']; 
require_once('connect.php'); 
$sth = $dbh->query("SELECT * FROM users where id = '$id';"); 
$sth->setFetchMode(PDO::FETCH_ASSOC); 
$eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); 
$eth->setFetchMode(PDO::FETCH_ASSOC); 
?> 

<div id="main"> 
    <div id="left"> 
    <form name="custInfo" action ="process.php" method ="post" > 
    <input type = "hidden" name ="formType" value="custInfo"/> 
    <?php while($row = $sth->fetch()){ ?> 
    <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> 
    <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> 
    <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> 
    <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> 
    <p></p> 
    <input type="submit" value="Update" /> 
    <?php }?> 
    </div> 

    <div id="mid"> 
    <form name="custCosts" action ="process.php" method ="post" > 
    <input type = "hidden" name ="formType" value="custCosts"/> 
    <?php while($row = $eth->fetch()){ ?> 
    <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> 
    <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> 
    <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> 
    <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> 
    <p></p> 
    <input type="submit" value="Update" /> 
    <?php }?> 
    </div> 

    <div id="right"> 
    <b>Total Balance</b> 
    <p> Money owed: </p> 
    <p> aaa total: </p> 
    <p> bbb total: </p> 
    <p> Total: </p> 
    <input type = "text" name ="pay" size ="20" /></p> 
    <input type="submit" value="Make Payment" /> 
    </div> 
<?php 
$dbh =null; 
?> 
</body> 
</html>

而對於所有的數據庫權謀代碼：

<?php 
require_once 'connect.php'; 
$formType = $_POST['formType']; 
$id = $_POST['id']; 
$firstName = $_POST['firstName']; 
$lastName = $_POST['lastName']; 
$country = $_POST['country']; 
$amountOwed = $_POST['amountOwed ']; 
$numAaa = $_POST['numAaa']; 
$numBbb = $_POST['numBbb']; 

if(empty($_POST['id'])) { 
$sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) 
VALUES ('$firstName', '$lastName', '$country')"); 
$sth->execute(); 

} elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ 
$sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); 
$sth->execute(); 

}elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ 
$sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) 
VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); 
$sth->execute(); 

}elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ 
$sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); 
$sth->execute(); 
} 

$dbh =null; 
?>

爲什麼形式甚至沒有顯示，如果沒有記錄？一個錯誤或我可能理解的東西....但表單仍然在HTML中，應該仍然是輸出，從我可以看到。爲什麼不是這種情況？

來源

2012-11-26 Chris Hodges

while($row = $sth->fetch())

這意味着：對於每個返回的行都做一些事情。如果沒有返回的行，那麼while中的任何內容都不會執行，因此它不會打印任何輸入！

您應該在rowCount中包含一個if，如果這等於0個打印輸入，那麼用戶可以填充它們。

<?php while($row = $sth->fetch()){ ?> 
    <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> 
    <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> 
    <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> 
    <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> 
    <p></p> 
    <input type="submit" value="Update" /> 
<?php 
    } 
    if($sth->rowCount()==0){ 
?> 
<p><input type = "hidden" name ="id" value=""/> 
    <p><input type = "text" name ="firstName" size ="30" value=""/> 
    <p><input type = "text" name ="lastName" size ="30" value=""/> 
    <p><input type = "text" name ="country" size ="30" value=""/> 
    <p></p> 
    <input type="submit" value="Update" /> 
<?php } ?>

來源

2012-11-26 10:54:22 Naryl

啊我覺得這麼愚蠢。你能否在你的答案中給出一個例子，這是我第一次嘗試編程，所以對我來說一切都是新的。 –

我編輯了我的答案，就像'if（$ sth-> rowCount（）== 0）'應該在每個while（$ row = $ sth-> fetch（））之前加上' – Naryl

窗體不顯示空記錄

回答

相關問題