轉換.string文件格式轉化成PHP數組格式

Question

希望你在做文件

因此，這裏是我的問題，我有一個用於translation.Please一個xyz.string文件中找到以下文件的一小部分。

/* name for an item that is duplicated in the UI, based on the original name */ 
"%@ (Copy)" = "%@ (kopi)"; 

/* display name for a book page template that is the first page of that section */ 
"%@ (First)" = "%@ (Første)"; 

/* display name for a book page template that represents a hardcover cover. the second argument is the cover type. */ 
"%@ (Hardcover, %@)" = "%1$@ (Hard innbinding, %2$@)"; 

/* display name for a book page template that represents a softcover cover. the second argument is the cover type. */ 
"%@ (Softcover, %@)" = "%1$@ (myk innbinding, %2$@)"; 

我想翻譯即轉換成一個PHP數組一樣

array(
array{ 
"%@ (First)"=>"%@ (Første)" 
}, 
array 
{ 
"@ (Hardcover, %@)"=>"%1$@ (Hard innbinding, %2$@)" 
} 
) 

等被指定on.The格式不是強制性的，但它應該是，我可以解決方法。

以下是文件格式

• 鍵 - 值對被分隔與等於字符（=）的以分號結束的說明書，和 （;）。

• 鍵和值由雙引號（「）包圍

• 佔位符的外觀可以是：％.2f，％d，％1個$ S（正則表達式 佔位符：/％[\ d |。] \ $ \ d * [DSF] {1} \ B + /）

• 註釋開始在該行的開始和跨越整個線 或多行

• 單行註釋開始用雙斜線（//）多線 註釋被包圍在/ * */

• 除非有任何 空白行評論被分配給下一個鍵 - 值對

  之間

我知道這可以通過PREG_MATCH_ALL來實現，但是我不能夠創建一個漂亮的正則表達式

下面

是我的代碼

$str=file_get_contents($_FILES['string']['tmp_name']); 
preg_match_all("|(\".+\"\;)|s",preg_quote($str),$match); 
echo "<pre/>";print_r($match);die; 

file_get_content後，我得到確切的字符串以下

/* name for an item that is duplicated in the UI, based on the original name */ "%@ (Copy)" = "%@ (kopi)"; /* display name for a book page template that is the first page of that section */ "%@ (First)" = "%@ (Første)"; /* display name for a book page template that represents a hardcover cover. the second argument is the cover type. */ "%@ (Hardcover, %@)" = "%1$@ (Hard innbinding, %2$@)"; 

如果有人能幫助我在這一點，我們將不勝感激

感謝 瑞安

Answer 1

主，正則表達式：

"([^"]+)"\s*=\s*"([^"]+)"; 

說明：

"([^"]+)"  # Every thing between double quotes 
\s*=\s*  # Equal sign preceded or followed by any number of spaces 
"([^"]+)"; # Again every thing between double quotes that ends to a ; 

PHP代碼：

$text = file_get_contents($_FILES['string']['tmp_name']); 
preg_match_all('#"([^"]+)"\s*=\s*"([^"]+)";#', $text, $match); 
$translate = array_combine($match[1], $match[2]); 
print_r($translate); 

的輸出您的示例文本將是：

Array 
(
    [%@ (Copy)] => %@ (kopi) 
    [%@ (First)] => %@ (Første) 
    [%@ (Hardcover, %@)] => %1$@ (Hard innbinding, %2$@) 
    [%@ (Softcover, %@)] => %1$@ (myk innbinding, %2$@) 
) 

Answer 2

你可以只讀取wohle字符串，然後使用：explode

$array = explode(';', $string);