1
我正在設計用於從客戶端接收文件的TCP服務器。它爲一個客戶端工作。但服務器需要響應多個客戶端。我不知道如何同時從客戶端接收多個文件。請幫幫我。C#多線程文件傳輸使用TCP
服務器代碼:
public partial class Form1 : Form
{
Thread t1;
int flag = 0;
string receivedPath = "yok";
public delegate void MyDelegate();
private string fileName;
public Form1()
{
t1 = new Thread(new ThreadStart(StartListening));
t1.Start();
InitializeComponent();
}
public class StateObject
{
// Client socket.
public Socket workSocket = null;
public const int BufferSize = 8096;
// Receive buffer.
public byte[] buffer = new byte[BufferSize];
}
public static ManualResetEvent allDone = new ManualResetEvent(true);
public void StartListening()
{
byte[] bytes = new Byte[8096];
IPEndPoint ipEnd = new IPEndPoint(IPAddress.Parse("127.0.0.1"), 9050);
Socket listener = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
try
{
listener.Bind(ipEnd);
listener.Listen(100);
SetText("Listening For Connection");
while (true)
{
allDone.Reset();
listener.BeginAccept(new AsyncCallback(AcceptCallback), listener);
allDone.WaitOne();
}
}
catch (Exception ex)
{
}
}
public void AcceptCallback(IAsyncResult ar)
{
allDone.Set();
Socket listener = (Socket)ar.AsyncState;
Socket handler = listener.EndAccept(ar);
StateObject state = new StateObject();
state.workSocket = handler;
handler.BeginReceive(state.buffer, 0, StateObject.BufferSize, 0, new AsyncCallback(ReadCallback), state);
flag = 0;
}
public void ReadCallback(IAsyncResult ar)
{
int fileNameLen = 1;
String content = String.Empty;
StateObject state = (StateObject)ar.AsyncState;
Socket handler = state.workSocket;
int bytesRead = handler.EndReceive(ar);
if (bytesRead > 0)
{
if (flag == 0)
{
fileNameLen = BitConverter.ToInt32(state.buffer, 0);
fileName = Encoding.UTF8.GetString(state.buffer, 4, fileNameLen);
receivedPath = @"D:\" + fileName;
flag++;
}
if (flag >= 1)
{
BinaryWriter writer = new BinaryWriter(File.Open(receivedPath, FileMode.Append));
if (flag == 1)
{
writer.Write(state.buffer, 4 + fileNameLen, bytesRead - (4 + fileNameLen));
flag++;
}
else
writer.Write(state.buffer, 0, bytesRead);
writer.Close();
handler.BeginReceive(state.buffer, 0, StateObject.BufferSize, 0, new AsyncCallback(ReadCallback), state);
}
}
else
{
Invoke(new MyDelegate(LabelWriter));
}
}
public void LabelWriter()
{
label1.Text = "Data has been received " + fileName;
}
private void Form1_FormClosed(object sender, FormClosedEventArgs e)
{
t1.Abort();
}
}
客戶端代碼:
public partial class Form1 : Form
{
string splitter = "'\\'";
string fName;
string[] split = null;
byte[] clientData;
public Form1()
{
InitializeComponent();
button2.Visible = false;
}
private void button1_Click_1(object sender, EventArgs e)
{
char[] delimiter = splitter.ToCharArray();
//openFileDialog1.ShowDialog();
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
textBox1.Text = openFileDialog1.FileName;
textBox2.AppendText("Selected file " + textBox1.Text);
button2.Visible = true;
}
else
{
textBox2.AppendText("Please Select any one file to send");
button2.Visible = false;
}
split = textBox1.Text.Split(delimiter);
int limit = split.Length;
fName = split[limit - 1].ToString();
if (textBox1.Text != null)
button1.Enabled = true;
}
private void button2_Click_1(object sender, EventArgs e)
{
Socket clientSock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
//IPAddress ip = new IPAddress;
byte[] fileName = Encoding.UTF8.GetBytes(fName); //file name
byte[] fileData = File.ReadAllBytes(textBox1.Text); //file
byte[] fileNameLen = BitConverter.GetBytes(fileName.Length); //lenght of file name
clientData = new byte[4 + fileName.Length + fileData.Length];
fileNameLen.CopyTo(clientData, 0);
fileName.CopyTo(clientData, 4);
fileData.CopyTo(clientData, 4 + fileName.Length);
textBox2.AppendText("Preparing File To Send");
clientSock.Connect("127.0.0.1", 9050); //target machine's ip address and the port number
clientSock.Send(clientData);
//clientSock.
clientSock.Close();
}
}
}
這應該已經適用於多個客戶:您接受連接,開始閱讀,並開始接受(罰款);你的閱讀回調過程,然後(如有必要)開始閱讀。這應該意味着您有很多正在進行的BeginRead操作。它應該已經在並行工作......? – 2012-02-17 10:37:17
你的問題是什麼?什麼不行?也許http://codereview.stackexchange.com/是一個更好的地方問。 – 2012-02-17 10:37:49
如果向服務器發送兩個文件意味着在「fileName = Encoding.UTF8.GetString(state.buffer,4,fileNameLen);」行中出現此錯誤「ArgumentOutOfRangeException was unhandled」 – Murugesan 2012-02-17 10:49:38