計算時間（年，月會考慮）

Question

我有兩個日期
06-Jan-2009和12-Dec-2010

我要計算這兩個日期之間（根據年份和月份）的日期差.. 。
我想得到答案2年。

但是，如果日期是06-Jan-2009而12-Oct-2010
那麼我就需要10個月的產量。

Answer 1

試試這個：

Declare @SDate DateTime ='06-Jan-2009' 
Declare @EDate DateTime ='12-Oct-2009' 


select case when DateDiff(M,@sDate,@EDate) <=12 
      then DateDiff(M,@sDate,@EDate) 
      else Round((Convert(Decimal(18,0) 
            ,DateDiff(M,@sDate,@EDate)/12.0)),0) end 

Answer 2

select Round((
Convert(Decimal(18,2),DateDiff(M,'06-Jan-2009','12-Dec-2010')/12.0)),0) 
as Years 

Answer 3

declare @Birthdate datetime 
declare @AsOnDate datetime 

declare @years int 
declare @months int 
declare @days int 
declare @hours int 
declare @minutes int 

--NOTE: date of birth must be smaller than As on date, 
--else it could produce wrong results 
set @Birthdate = '1989-11-30 9:27 pm' --birthdate 
set @AsOnDate = Getdate()   --current datetime 

--calculate years 
select @years = datediff(year,@Birthdate,@AsOnDate) 

--calculate months if it's value is negative then it 
--indicates after __ months; __ years will be complete 
--To resolve this, we have taken a flag @MonthOverflow... 
declare @monthOverflow int 
select @monthOverflow = case when datediff(month,@Birthdate,@AsOnDate) - 
    (datediff(year,@Birthdate,@AsOnDate) * 12) <0 then -1 else 1 end 
--decrease year by 1 if months are Overflowed 
select @Years = case when @monthOverflow < 0 then @years-1 else @years end 
select @months = datediff(month,@Birthdate,@AsOnDate) - (@years * 12) 

--as we do for month overflow criteria for days and hours 
--& minutes logic will followed same way 
declare @LastdayOfMonth int 
select @LastdayOfMonth = datepart(d,DATEADD 
    (s,-1,DATEADD(mm, DATEDIFF(m,0,@AsOnDate)+1,0))) 

select @days = case when @monthOverflow<0 and 
    DAY(@Birthdate)> DAY(@AsOnDate) 
then @LastdayOfMonth + 
    (datepart(d,@AsOnDate) - datepart(d,@Birthdate)) - 1 
     else datepart(d,@AsOnDate) - datepart(d,@Birthdate) end 

declare @hoursOverflow int 
select @hoursOverflow = case when datepart(hh,@AsOnDate) - 
    datepart(hh,@Birthdate) <0 then -1 else 1 end 
select @hours = case when @hoursOverflow<0 then 24 + 
    datepart(hh,@AsOnDate) - datepart(hh,@Birthdate) 
    else datepart(hh,@AsOnDate) - datepart(hh,@Birthdate) end 

declare @minutesOverflow int 
select @minutesOverflow = case when datepart(mi,@AsOnDate) - 
    datepart(mi,@Birthdate) <0 then -1 else 1 end 
select @minutes = case when @hoursOverflow<0 
    then 60 - (datepart(mi,@AsOnDate) - 
    datepart(mi,@Birthdate)) else abs(datepart 
     (mi,@AsOnDate) - datepart(mi,@Birthdate)) end 

select 
@Months=case when @days < 0 or DAY(@Birthdate)> DAY(@AsOnDate) then @Months-1 else @Months end 

Declare @lastdayAsOnDate int; 
set @lastdayAsOnDate = datepart(d,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@AsOnDate),0))); 
Declare @lastdayBirthdate int; 
set @lastdayBirthdate = datepart(d,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@Birthdate)+1,0))); 

if (@Days < 0) 
(
    select @Days = case when(@lastdayBirthdate > @lastdayAsOnDate) then 
     @lastdayBirthdate + @Days 
    else 
     @lastdayAsOnDate + @Days 
    end 
) 
print convert(varchar,@years) + ' year(s), ' + 
     convert(varchar,@months) + ' month(s), ' + 
     convert(varchar,@days) + ' day(s), ' + 
     convert(varchar,@hours) + ':'    + 
     convert(varchar,@minutes) + ' hour(s)' 

Answer 4

請嘗試下面的查詢

Declare @SDate DateTime ='01-Jan-2009' 
Declare @EDate DateTime ='12-Oct-2009' 

SET @EDate = DATEADD(M, 1, @EDate) 
select DateDiff(M,@sDate,@EDate) 

Answer 5

我認爲這是爲我工作：

DECLARE @start DATETIME='01-Jan-2008' 
DECLARE @end DATETIME='10-Nov-2011' 
DECLARE @duration INT 

--SELECT @start = '2011-10-10', @end = '2013-10-10' 
--select DATEPART(dd,@start) 
SET @Start = Dateadd(DAY, -(Datepart(DD, @Start) - 1), @Start) 

SET @end = Dateadd(DAY, -(Datepart(day, @end) - 1), @end) 
SET @end = Dateadd(day, Day(Dateadd(mm, Datediff(mm, -1, @end), -1)), @end) 

SELECT @duration = Datediff(mm, @Start, @end) 

SELECT CASE 
    WHEN @duration = 0 THEN NULL 
    WHEN @duration%12 = 0 THEN(CONVERT(NVARCHAR, @duration/12) + ' Year ') 
    WHEN @duration > 12 THEN(CONVERT(NVARCHAR, @duration/12) + ' Year ' + CONVERT(NVARCHAR, @duration % 12) + ' Month ') 
    ELSE (SELECT CONVERT(NVARCHAR, @duration % 12) + ' Month') 
END 

Answer 6

declare @Birthdate datetime 
declare @AsOnDate datetime 

declare @years varchar(4) 
declare @months varchar(3) 
declare @days varchar(3) 
declare @hours varchar(3) 
declare @minutes varchar(2) 

set @Birthdate = '1989-11-30 9:27 AM' --birthdate 
set @AsOnDate = getdate()  --current datetime 

select @years = datediff(year,@Birthdate,@AsOnDate) 
select @months = datediff(month,@Birthdate,@AsOnDate) - 
    (datediff(year,@Birthdate,@AsOnDate) * 12) 
select @days = datepart(d,@AsOnDate) - datepart(d,@Birthdate) 
select @hours = datepart(hh,@AsOnDate) - datepart(hh,@Birthdate) 
select @minutes = abs(datepart(mi,@AsOnDate) - datepart(mi,@Birthdate)) 

print @years + ' year(s), ' + 
     @months + ' month(s), ' + 
     @days + ' day(s), ' + 
     @hours + ':'    + @minutes + ' hour(s)' 

OUT PUT：