2011-10-24 59 views
1

我希望有一個case語句(或您建議的)生成多個結果,並且這些多個結果會反映在輸出中。但是,使用底部的示例,我沒有得到期望的結果。提前致謝。T-SQL:將列值移動到行值

目前:

ID Phase Total Hours Team1 Team2 Team3 
1 Test  50  25  10 15 
2 QA  60  20  20 20 
3 Impl  40  0  20 20 

尋找:

ID Phase Total Hours Team Name Team Hour 
1 Test  50  Team 1  25 
1 Test  50  Team 2  10 
1 Test  50  Team 3  15 
2 QA  60  Team 1  20 
2 QA  60  Team 2  20 
2 QA  60  Team 3  20 
3 Impl  40  Team 2  20 
3 Impl  40  Team 3  20 



Select ID, Phase, Total Hours, 
case 
When Team1 is not null and Team1 is >0 then 'Team1' 
When Team2 is not null and Team2 is >0 then 'Team2' 
When Team3 is not null and Team3 is >0 then 'Team3' 
end as 'Team Name', 

case 
When Team1.Hrs is not null and Team1.Hrs is >0 then Team1.Hrs 
When Team2.Hrs is not null and Team2.Hrs is >0 then Team2.Hrs 
When Team3.Hrs is not null and Team3.Hrs is >0 then Team3.Hrs 
end as 'Team Hours' 

From DB.DBNAME 
+0

您的示例查詢產生了什麼? – JNK

回答

0

醜陋,但是......

SELECT ID, Phase, [Total Hours], 'Team1' AS Team, Team1 AS [Team Hours] 
FROM DB.DBNAME 

UNION 

SELECT ID, Phase, [Total Hours], 'Team2' AS Team, Team2 AS [Team Hours] 
FROM DB.DBNAME 

UNION 

SELECT ID, Phase, [Total Hours], 'Team3' AS Team, Team3 AS [Team Hours] 
FROM DB.DBNAME 

您需要查詢返回任何像這樣的原因,和couldn」定期查詢並重新安排數據客戶端?

+0

創建存儲過程以執行一對多操作。感謝您的幫助。 –

2

使用UNPIVOT。例如:

;WITH t AS(
SELECT * FROM (VALUES(1,'Test',50,25,10,15),(2,'QA',60,20,20,20),(3,'Impl',40,0,20,20) 
      )x(ID, Phase, [Total Hours], Team1, Team2, Team3) 
) 
SELECT ID,Phase, [Total Hours], [Team Name], [Team Hour] 
FROM t 
UNPIVOT 
    ([Team Hour] FOR [Team Name] IN (Team1, Team2, Team3)) AS unpvt 
WHERE [Team Hour] > 0