SQL查詢從日期x到日期y查找可用房間y

Question

在以下關係模式中，如何導出未從日期範圍預訂的房間的可用「基本」類型。這是我的鏡頭。我在sqlplus

SELECT * 
    FROM ROOM r, BOOKING b 
    WHERE NOT EXISTS 
     (SELECT * FROM BOOKINGROOM br 
     WHERE br.ROOMNO = r.ROOMNO 
     AND br.BOOKINGID = b.BOOKINGID 
     AND ARRIVEDATE < '01-FEB-2013' 
     AND DEPARTDATE > '23-FEB-2013'); 

與甲骨文合作我也想被「罐裝查詢」查詢，所以我手動添加結束範圍，開始日期範圍。子查詢答案將是首選。

INSERT INTO BOOKING VALUES (2314, 1001, TO_DATE('10-MAR-2013', 'DD-MON-YYYY'), TO_DATE('15-MAR-2013', 'DD-MON-YYYY'), 1225.00); 

日期比較問題可能在下面的答案。

Answer 1

最簡單的方法是：

SELECT DISTINCT r.* 
FROM Room r 
LEFT JOIN BookingRoom br ON r.FloorNo = br.FloorNo AND r.RoomNo = br.RoomNo 
LEFT JOIN Booking b ON br.BookingId = b.BookingId 
     AND (b.ArriveDate <= &end_range AND b.DepartDate >= &start_range) 
WHERE b.BookingId IS NULL 
    AND r.Type = 'BASIC'; 

如果你絕對必須使用子查詢，試試這個：

SELECT DISTINCT r.* 
FROM Room r 
LEFT JOIN BookingRoom br ON r.FloorNo = br.FloorNo AND r.RoomNo = br.RoomNo 
LEFT JOIN Booking b ON br.BookingId = b.BookingId 
WHERE (b.BookingId IS NULL OR b.BookingId NOT IN (
     SELECT BookingId 
     FROM Booking 
     WHERE (ArriveDate <= &end_range AND DepartDate >= &start_range) 
)) AND r.Type = 'BASIC'; 

Answer 2

嘗試此查詢，無論是封閉，這將檢測衝突的預訂，封閉通過或部分與期望的日期範圍重疊。

SELECT DISTINCT r.* 
FROM Room r 
LEFT JOIN BookingRoom br ON r.FloorNo = br.FloorNo AND r.RoomNo = br.RoomNo 
LEFT JOIN Booking b ON br.BookingId = b.BookingId 
AND b.ArriveDate < &end_range AND b.DepartDate > &start_range 
WHERE b.BookingId IS NULL 
AND r.Type = 'BASIC';