嵌套typedef，有什麼不對

Question

有人在這裏看到錯誤。這個typedef A<B<T>::c>怎麼了？

template <const char *N> struct A { static const char *p; }; 
template <const char *N> const char *A<N>::p = N; 
template <class T> struct B { static const char c[1]; typedef A<B<T>::c> C; }; 
template <class T> const char B<T>::c[1] = ""; 
template <class T> struct D { static const char c[1]; typedef A<c> C; }; 
template <class T> const char D<T>::c[1] = ""; 

template <int& I> struct E { static int *ip; }; 
template <int& I> int* E<I>::ip = &I; 
template <class T> struct F { static int i; typedef E<F<T>::i> C; }; 
template <class T> int F<T>::i; 
template <class T> struct G { static int i; typedef E<i> C; }; 
template <class T> int G<T>::i; 

#define AS(X) if (!(X)) return 1; 
int main() 
{ 
    AS(B<int>::C::p == B<int>::c); 
    AS(B<float>::C::p == B<float>::c); 
    AS(B<float>::C::p != B<int>::c); 
    AS(D<int>::C::p == D<int>::c); 
    AS(D<float>::C::p == D<float>::c); 
    AS(D<float>::C::p != D<int>::c); 
} 

Answer 1

該代碼是正確的。編譯器中存在一個錯誤，您應該確保向開發人員報告此錯誤。