Oracle對類型名稱或子類型名稱的使用無效

Question

該塊正在使用什麼錯誤？請幫忙解決這個問題。 只根據where子句選擇一行。

表clazzes

Name Type   Nullable Default Comments 
---- ------------- -------- ------- -------- 
ID NUMBER(10)        
NAME VARCHAR2(100) Y   

PL/SQL塊：

declare 
type clazzes_row_type is record 
(clazz_rownum number, 
clazz_id clazzes.id%type, 
clazz_name clazzes.name%type); 
begin 
clazzes_row_type.clazz_rownum :=111; 
select id,name into clazzes_row_type.clazz_id,clazzes_row_type.clazz_name 
from clazzes where name ='leo1'; 
dbms_output.put_line(clazzes_row_type.clazz_id); 
dbms_output.put_line(clazzes_row_type.clazz_rownum); 
dbms_output.put_line(clazzes_row_type.clazz_name); 
end; 

例外：

ORA-06550: line 8, column 1: 
PLS-00330: invalid use of type name or subtype name 
ORA-06550: line 8, column 1: 
PL/SQL: Statement ignored 
ORA-06550: line 9, column 21: 
PLS-00330: invalid use of type name or subtype name 
ORA-06550: line 9, column 75: 
PL/SQL: ORA-00904: : invalid identifier 
ORA-06550: line 9, column 1: 
PL/SQL: SQL Statement ignored 
ORA-06550: line 11, column 22: 
PLS-00330: invalid use of type name or subtype name 
ORA-06550: line 11, column 1: 
PL/SQL: Statement ignored 
ORA-06550: line 12, column 22: 
PLS-00330: invalid use of type name or subtype name 
ORA-06550: line 12, column 1: 
PL/SQL: Statement ignored 
ORA-06550: line 13, column 22: 
PLS-00330: invalid use of type name or subtype name 
ORA-06550: line 13, column 1: 
PL/SQL: Statement ignored 

Answer 1

應聲明具有指定類型的變量。並用的構造器的變量：

​​

或與您的選擇：

begin 
    select 111,id,name into myvariable from clazzes where name ='leo1';