集團在子查詢

我在那有一個表AssignmentMaster我有一個數據集團在子查詢

AssignmentID   PaidAmount  RefundAmount UserID 
1      20    0    1 
2      10    5    1 
3      30    7    2 
4      25    0    3 
5      35    15    3 
6      10    3    1 
7      5    0    3 
8      10    0    3

現在我想找出相對於用戶ID的TotalNumberofAssignment以下幾列，即結果應該是：

UserID TotalAssignment TotalAssignmentofRefundAmount TotalPaidAmount TotalRefundAmount 
1    3     2      40    8 
2    1     1      30    7 
3    4     1      75    15

如何在MSSQL中獲得以上結果。你的任何幫助將幫助我很多。

來源

2011-06-14 Vijjendra

SELECT 
    UserID, 
    COUNT(AssignmentID) AS TotalAssignment, 
    SUM(SIGN(RefundAmount)) AS TotalAssignmentofRefundAmount, 
    SUM(PaidAmount) AS TotalPaidAmount, 
    SUM(RefundAmount) AS TotalRefundAmount 
FROM 
    MyTable 
GROUP BY 
    UserID

注：

SIGN(RefundAmount)作品如果REFUNDAMOUNT總是> = 0

如果沒有，更改爲

SUM(CASE WHEN RefundAmount <> 0 THEN 1 ELSE 0 END) AS TotalAssignmentofRefundAmount

來源

2011-06-14 12:21:23 gbn

「SIGN」解決方案的+1。 – 2011-06-14 12:24:23

對於新的sql關鍵字（SIGN）+1，你能告訴我SIGN是如何工作的嗎？謝謝Vijendra – Vijjendra 2011-06-14 12:29:03

SIGN與ABS（x）/ x相同。當x> 0時，SIGN（x）= 1。當x <0時，SIGN（x）= -1。 SIGN（0）= 0. – UltraCommit 2011-06-14 12:31:32

Select UserID, 
     count(1) as TotalAssignment, 
     sum(case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount, 
     sum(PaidAmount) as TotalPaidAmount , 
     sum(RefundAmount) as TotalRefundAmount 
From AssignmentMaster 
Group by UserID

來源

2011-06-14 12:22:17

select UserId, count (AssignmentID) as TotalAssignment, 
sum(case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount, 
sum(PaidAmount) as TotalPaidAmound, 
sum(RefundAmount) as TotalRefundAmount 
from AssignmentMaster 
group by UserID;

來源

2011-06-14 12:25:31 UltraCommit

AFAIK，SQL Server沒有'DECODE'功能，即Oracle特定的語法。您可以將其更改爲「CASE」聲明。 – 2011-06-14 12:27:09

剛剛更正，謝謝。 – UltraCommit 2011-06-14 12:27:52

此外，您可能需要將用戶ID添加到選擇列表中以提高結果的可讀性。 – eftpotrm 2011-06-14 13:37:56

爲了顯示怎麼辦這使用嵌套的SQL：

Select UserTotals.UserID, UserTotals.TotalAssignment, 
     Refunds.TotalAssignmentofRefundAmount, 
     UserTotals.TotalPaidAmount, UserTotals.TotalRefundAmount 
From (select  UserID, 
        Count(AssignmentID) [TotalAssignment], 
        Sum(PaidAmount)  [TotalPaidAmount], 
        sum(RefundAmount) [TotalRefundAmount] 
        From  @AssignmentMaster 
        Group By UserID 
     ) [UserTotals] Left Join 
     (Select  UserID, 
        Count(AssignmentID) [TotalAssignmentofRefundAmount] 
        From  @AssignmentMaster 
        Where  RefundAmount > 0 
        Group By UserID 
     ) [Refunds] On Refunds.UserID = UserTotals.UserID

來源

2011-06-14 12:37:52 pingoo

集團在子查詢

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