2016-11-28 12 views
1

我想提出一個簡單的刷卡畫廊,在這裏我只需要它來隱藏的默認瀏覽器滾動條,並通過圖像刷卡容器寬度。我爲滑動邏輯使用jQuery和TouchSwipe插件。到目前爲止,我已經寫了這個代碼:https://jsfiddle.net/drbj6zk8/5/。我已經加入容器中(通過獲取計算(div.swipe - div.swipe,包裝)和刷卡不應該去這些境外的iOS忽略了組隊,探索畫廊

$(函數(){

var currentTranslation = 0; 
var lastDistance = 0; 
var translationDelta = 0; 
var containerLengthArr = $('div.swipe-slide'); 
var containerLength = 0; 
var containerBorder = 0; 

$("#test5").swipe({ 
    swipeStatus: swipe2, 
    allowPageScroll: "horizontal" 
}); 
/*TODO*/ 

$.each(containerLengthArr, function(e) { 
    containerLength += ($(this).width() + 10); 
}) 
$('.swipe-wrapper').width(containerLength + 5); 
containerBorder = $('.swipe').width() - $('.swipe-wrapper').width(); 
console.log(containerBorder); 

//Swipe handlers 

function swipe2(event, phase, direction, distance) { 
    var check = $(this).children('.swipe-slide'); 
    if (phase == "end") { 
     translationDelta = 0; 
    } else { 
     translationDelta = lastDistance - distance; 
    } 
    /*Check direction*/ 
    if (direction == "right") { 
     currentTranslation -= translationDelta; 
    } else if (direction == "left") { 
     currentTranslation += translationDelta; 
    } 
    var distance2 = 0; 
    /*Limit slider to wrapper lenghth*/ 
    if (currentTranslation > 0) { 
     distance2 = "translateX(" + 0 + "px)"; 
     currentTranslation = 0; 
    } 
    else if (currentTranslation < containerBorder) { 
     distance2 = "translateX(" + containerBorder + "px)"; 
     currentTranslation = containerBorder; 
    } 
    else { 
     distance2 = "translateX(" + currentTranslation + "px)"; 
    } 

    check.css('transform', distance2); 
    lastDistance = distance; 

    console.log(currentTranslation); 
} 

});

當然,一切都運行在桌面瀏覽器和Android設備很好,但我碰到了與iOS設備的問題。我們絕對沒有跨不同設備(iPhone 5,iPhone 6,iPad的)行爲的一致性。在所有他們中我變得不同,更重要的是破碎的行爲(或者滑塊看起來不一樣,更重要的是,sw。超出設定的邊界)。

有誰知道我錯過了什麼或者是否有一些具體的要求,這在iOS工作?

回答