我對PHP編程還很陌生,我環顧四周,但我仍然感到困惑。我試圖更新我的用戶表中的圖像路徑,我不太確定如何去做。這是我將圖像放入數據庫的代碼,它可以插入圖像,但我不確定如何更新數據庫中的圖像圖片路徑以使用新插入的圖像,而不是使用者當他們創建一個帳戶時選擇。更新圖像路徑
// Make sure we didn't have an error uploading the image
($_FILES[$image_fieldname]['error'] == 0)
or handle_error("the server couldn't upload the image you selected.",
$php_errors[$_FILES[$image_fieldname]['error']]);
// Is this file the result of a valid upload?
@is_uploaded_file($_FILES[$image_fieldname]['tmp_name'])
or handle_error("you were trying to do something naughty. Shame on you!",
"upload request: file named " .
"'{$_FILES[$image_fieldname]['tmp_name']}'");
// Is this actually an image?
@getimagesize($_FILES[$image_fieldname]['tmp_name'])
or handle_error("you selected a file for your picture " .
"that isn't an image.",
"{$_FILES[$image_fieldname]['tmp_name']} " .
"isn't a valid image file.");
// Name the file uniquely
$now = time();
while (file_exists($upload_filename = $upload_dir . $now .
'-' .
$_FILES[$image_fieldname]['name'])) {
$now++;
}
// Finally, move the file to its permanent location
@move_uploaded_file($_FILES[$image_fieldname]['tmp_name'], $upload_filename)
or handle_error("we had a problem saving your image to " .
"its permanent location.",
"permissions or related error moving " .
"file to {$upload_filename}");
$insert_sql = "UPDATE users set user_pic_path WHERE user_id = $user_id =
replace(user_pic_path, '$upload_filename', '$upload_filename');
//insert the user into the database
mysql_query($insert_sql);
</code>
編輯: 我失蹤了「這是我固定的,現在還沒有SQL錯誤,它把圖片放到數據庫,但不能取代在數據庫中的圖像路徑我已經搞亂?在$ INSERT_SQL,但它仍然沒有更新爲新圖像路徑數據庫,我能做些什麼這是我的新的更新代碼:
<code>
$insert_sql = "UPDATE users WHERE user_id = $user_id set user_pic_path =
replace(user_pic_path, '$upload_filename', '$upload_filename')";
</code>
所以,你沒有任何計劃或編碼技巧,對吧?我敢打賭,有一些文件,你從哪裏得到這些代碼。 – djot
你覺得'user_pic_path'代表什麼? – djot
我確實有一些編程技巧,我只是比較新的PHP和堅持這一點。我不確定要在$ insert_sql中放入什麼來更新數據庫中的映像路徑。它可以很好地將圖像放入數據庫,但它不會替換路徑,這正是我期望做的 – nikito2003