歐拉項目＃17紅寶石 - 怎麼了？

我做在Ruby程序，我不知道爲什麼它不給我正確的答案歐拉項目＃17紅寶石 - 怎麼了？

問題：如果數字1至5字寫得出來：一，二，三，四，五，那麼總共使用3 + 3 + 5 + 4 + 4 = 19個字母。

如果所有從1到1000（包括1000）的數字都用文字寫出來，會用多少個字母？

注意：不要計算空格或連字符。例如，342（三百四十二）包含23個字母，115（一百一十五）包含20個字母。在編寫數字時使用「和」符合英國的用法。

我的代碼：

def number_to_words(n) 
    custom = {"0" => "", "1" => "one", "2" => "two", "3" => "three", "4" => "four", "5" => "five", "6" => "six", "7" => "seven", "8" => "eight", "9" => "nine", "10" => "ten", "11" => "eleven", "12" => "twelve", "13" => "thirteen", "14" => "fourteen", "15" => "fifteen", "16" => "sixteen", "17"=> "seventeen", "18" => "eighteen", "19" => "nineteen",} 
    tens = {"0" => "", "1" => "ten", "2" => "twenty", "3" => "thirty", "4" => "forty", "5" => "fifty", "6" => "sixty", "7" => "seventy", "8" => "eighty", "9" => "ninety"} 
    if n < 20 
     string = custom[n.to_s]  
    elsif n >= 20 && n < 100  
     string = tens[n.to_s[0]] + custom[n.to_s[1]] 
    elsif n % 1000 == 0 
     string = "onethousand" 
    elsif n >= 100 && n % 100 == 0 
     string = custom[n.to_s[0]] + "hundred" 
    else 
     string = custom[n.to_s[0]] + "hundred" + "and" + tens[n.to_s[1]] + custom[n.to_s[2]] 
    end 
end 

def letter_counter(x) 
    n = 1 
    sum = 0 
    while n < x + 1 
     sum = sum + number_to_words(n).length 
     print number_to_words(n).length, "\n" 
     n = n + 1 
     print n, "\n" 
    end 
    results = sum 
end

正確答案是

來源

2015-04-06 Dawid Płaneta

這不完全匹配SO格式。你最好在http://codereview.stackexchange.com/ – phts 2015-04-06 12:19:42

@phts上提出這個問題，這是不正確的。此代碼無法按預期工作，因此無法用於代碼視圖。請閱讀：http://meta.stackoverflow.com/questions/253975/be-careful-when-recommending-code-review-to-askers。謝謝！ – Vogel612 2015-04-06 12:21:12

我真的不知道紅寶石，但我知道這歐拉問題。在研究了你的代碼後，我將不得不猜測你的else語句是不正確的。

假設您的編號爲111，我認爲這屬於您的其他聲明。你建立一個字符串說，「onehundredandtenone」，而不是「onehundredandeleven」

所以它會在我看來，範圍從111 - 119將有不正確的字符串內置將拋出你的計數。事實上，這將是真正的211 - 219 ... 311 - 319 ...等...

來源

2015-04-06 13:08:59 Shar1er80

可以使用寶石人文化：

require 'humanize' 

p (1..1000).to_a.map(&:humanize).join.tr(" -", "").size

來源

2016-06-05 12:19:18 Arif

我不知道你有沒有已經知道什麼是錯誤的，但我調試它。

問題發生在111-120,211-220,311-320 ...... 附近。 number_to_words（111）變成「one hundred andtenone」

所以我又增加了兩行來考慮這些實例。

這裏的修改：

def number_to_words(n) 

custom = {"0" => "", "1" => "one", "2" => "two", "3" => "three", "4" => "four", "5" => "five", "6" => "six", "7" => "seven", "8" => "eight", "9" => "nine", "10" => "ten", "11" => "eleven", "12" => "twelve", "13" => "thirteen", "14" => "fourteen", "15" => "fifteen", "16" => "sixteen", "17"=> "seventeen", "18" => "eighteen", "19" => "nineteen",} 
tens = {"0" => "", "1" => "ten", "2" => "twenty", "3" => "thirty", "4" => "forty", "5" => "fifty", "6" => "sixty", "7" => "seventy", "8" => "eighty", "9" => "ninety"} 
if n < 20 
    string = custom[n.to_s]  
elsif n >= 20 && n < 100  
    string = tens[n.to_s[0]] + custom[n.to_s[1]] 
elsif n == 1000 
    string = "onethousand" 
elsif n >= 100 && n % 100 == 0 
    string = custom[n.to_s[0]] + "hundred" 
#changed this part 
elsif n >= 100 && (n % 100 < 20) 
    string = custom[n.to_s[0]] + "hundred" + "and" + custom[(n % 100).to_s[(0..1)]] 
else 
    string = custom[n.to_s[0]] + "hundred" + "and" + tens[n.to_s[1]] + custom[n.to_s[2]] 
    end 
    return string 
end

來源

2016-07-23 07:17:33

歐拉項目＃17紅寶石 - 怎麼了？

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