PHP數組字符串鍵添加數字在末尾

Question

美好的一天！

我在那裏我創建一個JSON字符串代碼塊，我有數據的動態數量，以便我需要的也是一個關鍵的動態名字..

if (mysql_num_rows($result) > 0) { 
    $response["members"] = array(); 
    $x = 0; 
    $members = array(); 
    while ($row = mysql_fetch_array($result)) { 
     $members = array(); 
     $members["member" + (string)$x] = array(); 
     $member["member_id"] = $row["member_id"]; 
     $member["firstname"] = $row["firstname"]; 
     $member["mi"] = $row["mi"]; 
     $member["lastname"] = $row["lastname"]; 
     $member["email"] = $row["email"]; 
     $member["username"] = $row["username"]; 
     $member["password"] = $row["password"]; 
     $member["guild_id"] = $row["guild_id"]; 
     $member["guild_name"] = $row["guild_name"]; 
     $member["guild_code"] = $row["guild_code"]; 
     array_push($members["member" + (string)$x], $member); 
     $x++; 
    } 
    array_push($response["members"], $members); 

    echo json_encode($response);; 
} 

jQuery的這種類型的方法工程..我的問題是，有什麼辦法，我可以實現它使用PHP？如果你知道我會很高興地知道...

Answer 1

1.Suggestion：-stop使用棄用的mysql_* .Move +移除（PHP5 + PHP7）版本朝向mysqli_* OR PDO與prepared statements（防止SQL注入）

沿2.爲什麼創建不必要的陣列和多個push.No需要要做到這一點。像下面這樣： -

$response["members"] = array();//put outside 
if (mysql_num_rows($result) > 0) { 
    $x = 0; 
    while ($row = mysql_fetch_array($result)) { 
     $response["members"][$x]["member_id"] = $row["member_id"]; //assign value directly to the resultant array 
     $response["members"][$x]["firstname"] = $row["firstname"]; 
     $response["members"][$x]["mi"] = $row["mi"]; 
     $response["members"][$x]["lastname"] = $row["lastname"]; 
     $response["members"][$x]["email"] = $row["email"]; 
     $response["members"][$x]["username"] = $row["username"]; 
     $response["members"][$x]["password"] = $row["password"]; 
     $response["members"][$x]["guild_id"] = $row["guild_id"]; 
     $response["members"][$x]["guild_name"] = $row["guild_name"]; 
     $response["members"][$x]["guild_code"] = $row["guild_code"]; 
     $x++; 
    } 
} 

if(count($response["members"])>0){ //check finally that array is not empty 
echo json_encode($response); //echo json encoded array data 
} 

Answer 2

如果你想達到的members數組包含鍵作爲member0，member1等個人記錄，那麼你可以爲進行：

if (mysql_num_rows($result) > 0) { 
    $x = 0; 
    $members = array(); 
    while ($row = mysql_fetch_array($result)) { 
     $member = array(); 
     $member["member_id"] = $row["member_id"]; 
     $member["firstname"] = $row["firstname"]; 
     $member["mi"] = $row["mi"]; 
     $member["lastname"] = $row["lastname"]; 
     $member["email"] = $row["email"]; 
     $member["username"] = $row["username"]; 
     $member["password"] = $row["password"]; 
     $member["guild_id"] = $row["guild_id"]; 
     $member["guild_name"] = $row["guild_name"]; 
     $member["guild_code"] = $row["guild_code"]; 
     $members["member$x"] = $member; 
     $x++; 
    } 
    $response["members"] = $members; 

    echo json_encode($response); 
}