我創建了這個查詢來顯示我的自動完成框與jQuery。它工作完美。高級自動完成列表
<?php
require_once('database.php');
if(isset($_POST['queryString'])) {
$queryString = $dbc->real_escape_string($_POST['queryString']);
if(strlen($queryString) >0) {
$q = "SELECT keyword
FROM (
SELECT tname AS keyword FROM t
UNION
SELECT sname AS keyword FROM sub
UNION
SELECT cname AS keyword FROM c
UNION
SELECT iname AS keyword FROM i
) s
WHERE keyword LIKE '%$queryString%'
LIMIT 10";
$r = mysqli_query ($dbc, $q);
if($q) {
while ($row = mysqli_fetch_array($r, MYSQL_ASSOC)) {
echo '<li onClick="fill(\''.$row['keyword'].'\');">'.$row['keyword'].'</li>';
}
} else {
echo 'ERROR: There was a problem with the query.';
}
} else {
}
} else {
echo 'There should be no direct access to this script!';
}
?>
與此查詢顯示自動完成列表與科目,導師名稱,城市根據關鍵字。現在我需要修改具有更多值的自動完成列表。例如,我想在列表中顯示一個導師姓名,以顯示他/她的當前城市,他/她的個人資料圖片等。這與Facebook搜索類似。
這是我的城市和地址表
# --------------
# Address Table
# --------------
CREATE TABLE address (
address_id INT(4) UNSIGNED NOT NULL AUTO_INCREMENT,
address_one VARCHAR(40) NOT NULL,
address_two VARCHAR(40) DEFAULT NULL,
city_id INT(4) UNSIGNED NOT NULL,
PRIMARY KEY (address_id),
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
# --------------
# City Table
# --------------
CREATE TABLE city(
city_id INT(4) UNSIGNED NOT NULL AUTO_INCREMENT,
city_name VARCHAR(30) NOT NULL,
district_id INT(2) UNSIGNED NOT NULL,
PRIMARY KEY (city_id),
UNIQUE (city_name)
) ENGINE=MyISAM;
我怎樣才能做到這一點?
我不是在談論這個問題,但對其他問題你都問,並沒有接受一個答案。檢查這裏的問題http://stackoverflow.com/users/1543817/user1543817?tab=questions – Sudar
行..我做到了..謝謝 – ugnuku