根據URL參數返回一個特定的XML節點

Question

希望我正確地問這個問題，因爲我猜這將需要PHP實現。

我想要做的是通過URL返回XML數據的特定節點和所有子節點。

例如：mydomain.com/myphpfile.php?book_id=1 &標題= 「我的書名」

所以通過顯示的URL上方將返回以下XML數據僅

<Books> 
    <book id="1"> 
     <title>My Book Title</title> 
     <author>John Doe</author> 
     <genre>Horror</genre> 
     <description>Some long text description</description> 
    </book> 
    </Books> 

這僅僅是XML的一個例子：

<Books> 
    <book id="1"> 
     <title>My Book Title</title> 
     <author>John Doe</author> 
     <genre>Horror</genre> 
     <description>Some long text description</description> 
    </book> 

     <book id="2"> 
     <title>My Book Title</title> 
     <author>John Doe</author> 
     <genre>Comedy</genre> 
     <description>Some long text description</description> 
    </book> 

     etc 
</Books> 

Answer 1

$book_id = 1; 
$title = 'My Book Title'; 

$xml = simplexml_load_string($str); 
// find not suitable items - having incorrect id or title 
$dels = $xml->xpath('//book[@id != '. $book_id .' or title != "'. $title .'"]'); 
    // delete found books from xml 
    foreach($dels as $node) { 
    unset($node->{0}); 
    } 

echo $xml->saveXML();