循環依賴於天數

Question

我正在做一個REST調用，如果該字段是不是有在哈希表更新這些3場，以更新其現場決定，默認情況下它會更新「AA」

每次撥打電話時，服務器上的計數器也會增加。所以在3次運行後，所有字段都在服務器上，並且它總是更新「AA」，因爲它是默認值，現在我希望字段更新由計數器選擇。因此，流程繼續爲AA，BB，CC - AA，BB，CC - AA，BB，CC。如何？

//on 1st update call,it updates AA and Counter is set to =1 
    //2nd update call,it update BB = Counter is set to =2 
    //3rd update call,it update CC = Counter is set to =3 
    //4th update call,it update AA = Counter is set to =4 
    //5th update call,it update AA = Counter is set to =5 
    //6th update call,it update AA = Counter is set to =6 

if (fieldValues.containsKey("COUNTER")) { 
      counter= fieldValues.get("COUNTER"); 
}// how can we use this counter to select the next field 

HashMap<String, String> fieldValues = [{key,value},{key,value},{key,value}......] 
String [] FieldsToUpdate = ["AA","BB","CC"]; 
String xxxFieldToUpdate = FieldsToUpdate[0];// so default is "AA" 

for(String Field : FieldsToUpdate){ 
     if(!fieldValues.containsKey(Field)){ 
      xxxFieldToUpdate = Field.trim(); 
      break; 
     } 
    } 
    // Solved by calling a new method which reset the Iterator // 

    String fieldToUpdate = ""; 
    counter= fieldValues.get("COUNTER"); 
    Iterator it = fieldsToUpdate.iterator(); 
    for(int i=0; i<counter; i++) { 
    if(!it.hasNext()) // if you are at the end of the list reset iterator 
    it = fieldsToUpdate.iterator(); 
    String res = it.next().toString(); 
    fieldToUpdate = res; 
    } 
    return fieldToUpdate; 

Answer 1

也許使用不同的FOR循環，像這樣。

for(int i = 0; i < 3; i ++) 
{ 
if(!fieldValues.containsKey(FieldsToUpdate[i])){ 
      xxxFieldToUpdate = FieldsToUpdate[i].trim(); 
      break; 
     } 
} 

Answer 2

//通過調用其重置迭代器//

String fieldToUpdate = ""; 
counter= fieldValues.get("COUNTER"); 
Iterator it = fieldsToUpdate.iterator(); 
    for(int i=0; i<counter; i++) { 
    if(!it.hasNext()) // if you are at the end of the list reset iterator 
    it = fieldsToUpdate.iterator(); 
    String res = it.next().toString(); 
    fieldToUpdate = res; 
} 
return fieldToUpdate;