（Symfony的3.1）PHP主義集團機構通過日期時間

Question

我通過堆棧日期時間試圖組我的實體。每個實體都有以下各列：ID，設備，啓動，停止，ip地址。

我希望能夠得到一個範圍的日期，並將它們按日期（天）範圍內的實體與每一天有多少小時有以下。

這是我迄今爲止

public function findAllGroupedByDate($from = null, $to = null) 
{ 
    $from = isset($from) && !is_null($from) ? $from : date('Y-m-d', time()); 
    $to = isset($to) && !is_null($to) ? $to : date('Y-m-d', time()); 

    $from = new \DateTime("-3 days"); 
    $to = new \DateTime("1 days"); 

    $from = date("Y-m-d", $from->getTimestamp()); 
    $to = date("Y-m-d", $to->getTimestamp()); 

    $q = $this->getEntityManager()->createQueryBuilder() 
     ->select("timelog") 
     ->from("AppBundle:Timelog", "timelog") 
     ->where("timelog.start BETWEEN :from AND :to") 
     ->setParameter("from", $from) 
     ->setParameter("to", $to) 
     ->orderBy("timelog.stop") 
     ->getQuery(); 
    return $q->getResult(); 
} 

public function findFromToday() 
{ 
    $q = $this->createQueryBuilder('t') 
      ->select('t.id', 't.start', 't.stop', 't.stop') 
      ->where("t.start >= :today") 
      ->setParameter("today", date('Y-m-d', time())) 
      ->groupBy("t.id", "t.stop") 
      ->orderBy("t.start", "asc") 
      ->getQuery(); 

    return $q->getResult(); 
} 

這是我的倉庫類的代碼。

，並從我的控制器看起來像這樣的代碼：

$timelogsRepo = $this->getDoctrine()->getRepository('AppBundle:Timelog'); 

// Grab logs from today 
$timelogsCollection = $timelogsRepo->findFromToday(); 
$tmpLogs = $timelogsRepo->findAllGroupedByDate(); 

// THIS SECTION IS FOR CALCULATING HOURS & MINUTES 
    $minutes = 0; 
    $hours = 0; 
    foreach($timelogsCollection as $log) 
    { 
     $time1 = $log['start']; 
     $time2 = $log['stop']; 
     $interval = date_diff($time1, $time2); 

     $hours += $interval->h; 
     $minutes += $interval->i; 

    } 


    $minutes = $minutes >59 ? $minutes/60 : $minutes; 


    return $this->render(':Timelog:index.html.twig', [ 
     'timelogs' => $logsOut, 
     'hours' => $hours, 
     'minutes' => $minutes 
    ]); 

到目前爲止我能計算總花費的時間對於一個給定的一天（只有一天）。現在我想獲得全部實體，由同日（日）他們組和間隔返回數據。

示例數據庫表看起來像這樣[ID，DEVICE_ID，啓動，停止，ip地址]

1 1 2016-08-09 09:00:06 2016-08-09 12:00:06 127.0.0.1 
2 1 2016-08-08 07:00:00 2016-08-08 13:00:00 127.0.0.1 
3 1 2016-08-08 13:10:00 2016-08-08 15:05:00 127.0.0.1 

因此，在這種情況下，我的輸出會是這樣的：

[ 
    0 => ["date" => "2016-08-09", "hours" => 9.00, "ipaddress" =>  "127.0.0.1"], 
    1 => ["date" => "2016-08-09", "hours" => 1.45, "ipaddress" => "127.0.0.1"] 
] 

的時間間隔取決於啓動和停止都是類型的DateTime

我試過使用doctrine-extensions：oro/doctrine-extensions但是現在我得到異常錯誤：

[2/2] QueryException: [Syntax Error] line 0, col 50: Error: Expected Unit is not valid for TIMESTAMPDIFF function. Supported units are: "MICROSECOND, SECOND, MINUTE, HOUR, DAY, WEEK, MONTH, QUARTER, YEAR", got 'stop' 

我的倉庫方法是這樣的：

public function findByToday() 
{ 
    $fields = array(
     'DATE(stop) as stop', 
     'TIME(SUM(TIMESTAMPDIFF(stop, start))) AS tdiff', 
     'device_id', 
     'ipaddress' 
    ); 

    $q = $this->createQueryBuilder('t') 
     ->select($fields) 
     ->where('DATE(stop) = :today') 
     ->setParameter('today', date('Y-m-d', time())) 
     ->groupBy('device_id') 
     ->getQuery(); 

    return $q->getResult(); 

} 

我的數據庫表：

id device_id start stop ipaddress 
5 1 2016-08-09 09:00:06 2016-08-09 12:00:06 127.0.0.1 
6 1 2016-08-08 07:00:00 2016-08-08 13:00:00 127.0.0.1 
7 1 2016-08-08 13:10:00 2016-08-08 15:05:00 127.0.0.1 

BTW我使用的Symfony 3，可能是這個問題？

Answer 1

根據您上面的表格（如果我猜中了）我想嘗試直接與MYSQL獲取數據，然後工作，我的方式來學說。

如果你有如下表：

CREATE TABLE `testdevices` (
    `id` INT(11) NOT NULL AUTO_INCREMENT, 
    `device` INT(11) NULL DEFAULT NULL, 
    `dstart` DATETIME NULL DEFAULT NULL, 
    `dend` DATETIME NULL DEFAULT NULL, 
    `ip` TINYTEXT NULL, 
    PRIMARY KEY (`id`) 
); 

並通過下面的測試數據填充（我已經創建了兩個設備，第二個是爲精確3小時方便地活躍在今天的日期）：

mysql> select * from testdevices; 
+----+--------+---------------------+---------------------+-----------+ 
| id | device | dstart    | dend    | ip  | 
+----+--------+---------------------+---------------------+-----------+ 
| 1 |  1 | 2016-08-09 09:00:06 | 2016-08-09 12:00:06 | 127.0.0.1 | 
| 2 |  1 | 2016-08-08 07:00:00 | 2016-08-08 13:00:00 | 127.0.0.1 | 
| 3 |  1 | 2016-08-08 13:10:00 | 2016-08-11 22:14:46 | 127.0.0.1 | 
| 4 |  2 | 2016-08-11 13:00:00 | 2016-08-11 14:00:00 | 127.0.0.1 | 
| 5 |  2 | 2016-08-11 15:00:00 | 2016-08-11 16:00:00 | 127.0.0.1 | 
| 6 |  2 | 2016-08-11 17:00:00 | 2016-08-11 18:00:00 | 127.0.0.1 | 
+----+--------+---------------------+---------------------+-----------+ 
6 rows in set (0.00 sec) 

下面的MySQL查詢會那麼相信將數據輸出你想要的：

SELECT DATE(dend) as dend, TIME(SUM(TIMEDIFF(dend, dstart))) AS tdiff, device, ip 
FROM testdevices WHERE DATE(dend) = '2016-08-11' 
GROUP BY device ; 

結果將如下所示：

+------------+----------+--------+-----------+ 
| dend  | tdiff | device | ip  | 
+------------+----------+--------+-----------+ 
| 2016-08-11 | 81:04:46 |  1 | 127.0.0.1 | 
| 2016-08-11 | 03:00:00 |  2 | 127.0.0.1 | 
+------------+----------+--------+-----------+ 
2 rows in set (0.01 sec) 

請注意，第二個設備時間是正確的。現在，剩下的問題是如何做到這一點的學說。據我所知TIMEDIFF功能不是學說的一部分，又是那麼我會建議2種不同的方法：

1. 自己寫的功能，如 http://www.doctrine-project.org/2010/03/29/doctrine2-custom-dql-udfs.html#date-diff（有例子DATEDIFF在這個環節，因此很容易可調），或
2. 使用https://packagist.org/packages/oro/doctrine-extensions

教義/ Symfony2中你的最終處置庫函數安裝會是這個樣子奧羅/學說的擴展：

$fields = array(
      'DATE(dend) as dend', 
      'SUM(TIMESTAMPDIFF(SECOND, dend, dstart)) AS tdiff', 
      'device', 
      'ip' 
     ); 

public function findFromToday() 
{ 
    $q = $this->createQueryBuilder('t') 
      ->select($fields) 
      ->where('DATE(dend) = :today') 
      ->setParameter('today', date('Y-m-d', time())) 
      ->groupBy('device') 
      ->getQuery(); 

    return $q->getResult(); 

我寫了這個函數，根本不用測試它，從我的頭頂開始。你可能會發現它失敗了。由於TIMESTAMPDIFF需要指定單位，因此這會產生幾秒鐘的時間差。 安裝奧羅/學說的擴展與

composer require oro/doctrine-extensions