連續重組結果

Question

我認爲這是一個非常簡單的問題，但我沒有找到有用的東西。

我做3點的選擇，看起來像這樣：

SELECT count(*) as nbTable1 
FROM table1, joinTable 
WHERE table1.A = joinTable.A; 

SELECT count(*) as nbTable2 
FROM table2, joinTable 
WHERE table1.A = joinTable.A; 

SELECT count(*) as nbTable3 
FROM table3, joinTable 
WHERE table1.A = joinTable.A; 

我想組的結果在一排：

nbTable1 | nbTable2 | nbTable3 | 
-------------------------------- 
     12 |  8 |  15 | 

---

我試圖UNION的結果，但我得到

nbTable1 | 
---------- 
     12 | 
     8 | 
     15 | 

---

由於我在每個請求中使用了joinTable，因此我無法在單個select中完成...可以幫助我嗎？ :)

Answer 1

SELECT 
     (SELECT count(*) 
     FROM table1, joinTable 
     WHERE table1.A = joinTable.A) nbTable1, 
     (SELECT count(*) 
     FROM table2, joinTable 
     WHERE table2.A = joinTable.A) nbTable2, 
     (SELECT count(*) 
     FROM table3, joinTable 
     WHERE table3.A = joinTable.A) nbTable3 
FROM DUAL;