Python - 如何驗證tkinter輸入字段

Question

在我的程序中，我有一個sqlite數據庫，其中數據通過tkinter gui中的輸入小部件附加到數據庫。我喜歡它，所以數據只在數據庫驗證後附加到數據庫中，因爲目前沒有驗證。

例如，在我的功能在其下面我的數據庫追加的customerID，名，姓，地址和電話號碼，以客戶表。我喜歡它，所以customerID條目只接受整數，forename，surname和address爲NOT NULL，phoneNumberEntry只接受整數。

我看到人們使用validatecommand，但我不認爲，因爲我已經在使用一個命令來添加數據到數據庫中，我將能夠實現這一點。

def appendToCustomerTableEntry(event): 
    top = Toplevel() 
    top.title("Add to customer table") 

    Label(top, text = "customerID: ").grid(sticky = E) 

    customerIDEntry = Entry(top) 
    customerIDEntry.grid(row = 0, column = 1) 

    Label(top, text = "Forename: ").grid(row = 1, sticky = E) 

    customerForenameEntry = Entry(top) 
    customerForenameEntry.grid(row = 1, column = 1) 

    Label(top, text = "Surname: ").grid(row = 2, sticky = E) 

    customerSurnameEntry = Entry(top) 
    customerSurnameEntry.grid(row = 2, column = 1) 

    Label(top, text = "Address: ").grid(row = 3, sticky = E) 

    customerAddressEntry = Entry(top) 
    customerAddressEntry.grid(row = 3, column = 1) 

    Label(top, text = "Phone Number: ").grid(row = 4, sticky = E) 

    customerPhoneNumberEntry = Entry(top) 
    customerPhoneNumberEntry.grid(row = 4, column = 1) 

    exitButton = Button(top, text = "Exit", command = top.destroy) 
    exitButton.grid(row = 5, column = 2, sticky = W) 

    appendButton = Button(top, text = "Append", command = lambda:appendToCustomerTable 
        (customerIDEntry.get(), customerForenameEntry.get(), customerSurnameEntry.get(), 
        customerAddressEntry.get(), customerPhoneNumberEntry.get())) 
    appendButton.grid(row = 5, column = 1, sticky = E) 


def appendToCustomerTable(customerID, Forename, Surname, Address, TelephoneNumber): 
    c.execute("INSERT INTO customerTable VALUES (?, ?, ?, ?, ?);", (customerID, Forename, Surname, Address, TelephoneNumber)) 
    conn.commit() 

Answer 1

這是一個sql sanitation的問題，還是一個python編程的問題？

如果SQL衛生，你需要找出SQL字符串或字符來拒絕這樣做，也有可能是庫。 https://www.owasp.org/index.php/SQL_Injection_Prevention_Cheat_Sheet

通過編程，人們可以運行if語句，更改操作的順序並使用字符串替換。 http://bobby-tables.com/python.html

在您的代碼中，您要注意的事情是有人試圖通過您的字段發佈代碼。仔細查看最後一個鏈接。

Answer 2

firsty嘗試「dont repeat your self」

# you can declare here the input type of your argument default and the type of them 
def build(ui_title = [], int_arg = 0): 
    # on top you can also assert the input 
    # continue only if ui_title is True else give a AssertionError 
    assert (ui_title), "list is empty!!!" 

    # lets check int_arg for int 
    assert (int_arg==int), "{0} except int get {1}".format(int_arg ,type(int_arg)) 

    for row,text in enumerate(ui_title): 
     Label(top, text = str(text)).grid(sticky = E) 
     customerIDEntry = Entry(top) 
     customerIDEntry.grid(row = int(row), column = 1) 
     if text=="Exit": 
      exitButton = Button(top, text = str(text), command = top.destroy) 
      exitButton.grid(row = int(row), column = 2, sticky = W) 

ui_title = ["customerID", "Forename: ", "Surname: ", "Address: ", "Phone Number: ", "Exit"] 
build(ui_title) # will work 
build(ui_title, int_arg = "Hallo") # will not work, because int_arg get string and the build method will raise a AssertionError