造成的：org.hibernate.QueryException：無法解析屬性：姓氏

我有這樣的代碼工作有我需要的輸出造成的：org.hibernate.QueryException：無法解析屬性：姓氏

String hql = "FROM Employee ORDER BY last_name"; 
Query query = session.createQuery(hql); 
employeeList = query.list();

我想這個代碼，但它無法

String hql = "FROM Employee E ORDER BY E.last_name"; 
Query query = session.createQuery(hql); 
employeeList = query.list();

這裏異常

Exception in thread "main" java.lang.IllegalArgumentException: org.hibernate.QueryException: could not resolve property: last_name of: com.hibernate.exercise6.model.Employee [FROM com.hibernate.exercise6.model.Employee E ORDER BY E.last_name] 
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:131) 
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:155) 
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:162) 
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:631) 
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:101) 
at com.hibernate.exercise6.service.EmployeeFunctions.listEmployees(EmployeeFunctions.java:208) 
at com.hibernate.exercise6.app.GUIMain.displayListMenu(GUIMain.java:329) 
at com.hibernate.exercise6.app.GUIMain.manageRecords(GUIMain.java:140) 
at com.hibernate.exercise6.app.GUIMain.main(GUIMain.java:62) 
Caused by: org.hibernate.QueryException: could not resolve property: last_name of: com.hibernate.exercise6.model.Employee [FROM com.hibernate.exercise6.model.Employee E ORDER BY E.last_name] 
at org.hibernate.QueryException.generateQueryException(QueryException.java:120) 
at org.hibernate.QueryException.wrapWithQueryString(QueryException.java:103) 
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:218) 
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:142) 
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:115) 
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:77) 
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:152) 
at org.hibernate.internal.AbstractSharedSessionContract.getQueryPlan(AbstractSharedSessionContract.java:521) 
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:623) 
... 5 more 
Caused by: org.hibernate.QueryException: could not resolve property: last_name of: com.hibernate.exercise6.model.Employee 
at org.hibernate.persister.entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:62) 
at org.hibernate.persister.entity.AbstractPropertyMapping.toType(AbstractPropertyMapping.java:56) 
at org.hibernate.persister.entity.AbstractEntityPersister.toType(AbstractEntityPersister.java:1801) 
at org.hibernate.hql.internal.ast.tree.FromElementType.getPropertyType(FromElementType.java:393) 
at org.hibernate.hql.internal.ast.tree.FromElement.getPropertyType(FromElement.java:505) 
at org.hibernate.hql.internal.ast.tree.DotNode.getDataType(DotNode.java:660) 
at org.hibernate.hql.internal.ast.tree.DotNode.prepareLhs(DotNode.java:264) 
at org.hibernate.hql.internal.ast.tree.DotNode.resolve(DotNode.java:204) 
at org.hibernate.hql.internal.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:109) 
at org.hibernate.hql.internal.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:104) 
at org.hibernate.hql.internal.ast.HqlSqlWalker.resolve(HqlSqlWalker.java:1013) 
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.expr(HqlSqlBaseWalker.java:1286) 
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.orderExpr(HqlSqlBaseWalker.java:1860) 
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.orderExprs(HqlSqlBaseWalker.java:1657) 
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.orderClause(HqlSqlBaseWalker.java:1630) 
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:652) 
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:311) 
at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:259) 
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:262) 
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:190) 
... 11 more

Employee.java

package com.hibernate.exercise6.model; 

import java.util.Set; 
import java.util.Comparator; 

public class Employee extends Id{ 
private int uniqueId; 
private Name nameInfo; 
private Address addressInfo; 
private OtherInfo otherInfo; 
private Set contact; 
private Set role; 

public Employee() {} 

public Employee(Name nameInfo, Address addressInfo, OtherInfo otherInfo){ 
    this.nameInfo = nameInfo; 
    this.addressInfo = addressInfo; 
    this.otherInfo = otherInfo; 
} 

public void setId(int uniqueId){ 
    this.uniqueId = uniqueId; 
} 
public int getId(){ 
    return uniqueId; 
} 

public void setName(Name nameInfo){ 
    this.nameInfo = nameInfo; 
} 
public Name getName(){ 
    return nameInfo; 
} 

public void setAddress(Address addressInfo){ 
    this.addressInfo = addressInfo; 
} 
public Address getAddress(){ 
    return addressInfo; 
} 

public void setOtherInfo(OtherInfo otherInfo){ 
    this.otherInfo = otherInfo; 
} 
public OtherInfo getOtherInfo(){ 
    return otherInfo; 
} 

public void setContacts(Set contact){ 
    this.contact = contact; 
} 
public Set getContacts(){ 
    return contact; 
} 

public void setRole(Set role){ 
    this.role = role; 
} 
public Set getRole(){ 
    return role; 
} 

public static Comparator<Employee> employeeGwaComparator = new Comparator<Employee>(){ 
    public int compare(Employee emp1, Employee emp2){ 
     String emp1Gwa = String.valueOf(emp1.otherInfo.getGwa()); 
     String emp2Gwa = String.valueOf(emp2.otherInfo.getGwa()); 

     return emp1Gwa.compareTo(emp2Gwa); 
    }  
}; 
}

Name.java

package com.hibernate.exercise6.model; 

public class Name{ 
private String firstName, 
           lastName, 
           middleName, 
           suffix, 
           title; 

public Name() {} 

public Name(String title, String firstName, String middleName, String lastName, String suffix){ 
    this.title = title; 
    this.firstName = firstName; 
    this.middleName = middleName; 
    this.lastName = lastName; 
    this.suffix = suffix; 
} 

public void setTitle(String title){ 
    this.title = title; 
} 
public String getTitle(){ 
    return title; 
} 

public void setFirstName(String firstName){ 
    this.firstName = firstName; 
} 
public String getFirstName(){ 
    return firstName; 
} 

public void setMiddleName(String middleName){ 
    this.middleName = middleName; 
} 
public String getMiddleName(){ 
    return middleName; 
} 

public void setLastName(String lastName){ 
    this.lastName = lastName; 
} 
public String getLastName(){ 
    return lastName; 
} 

public void setSuffix(String suffix){ 
    this.suffix = suffix; 
} 
public String getSuffix(){ 
    return suffix; 
} 
}

應該不是第一碼和第二碼行爲相同的方式？只有一個別名被引入，我是否正確？

來源

2016-07-21 Dee

你可以張貼'Employee'代碼？ – Saravana

您的「Employee」類中沒有'last_name'。它應該是你的HQL中的'lastName'。 –

在HQL中，您可以通過實體的屬性訪問實際列名稱。在你的情況下，屬性名稱是lastName和列名是last_name。因此，如果您使用HQL，則必須使用屬性，如果要實施NativeQuery，則可以使用列名稱。
您在具有name財產Employee實體執行SELECT條款，這最後有lastName物業爲好。所以，你的查詢必須寫爲波紋管：
```
String hql = "FROM Employee E ORDER BY E.name.lastName"; 
Query query = session.createQuery(hql); 
employeeList = query.list(); 
```

來源

2016-07-21 08:16:58

很好的答案！我想添加到答案 - 使用Criteria API。其保存的查詢語言。沒有你，Hibernate將構造查詢。看起來像 return createCriteria（Employee.class） .addOrder（Order.asc（「name」））。list（） – flybox

它實際上應該是'E.Name.lastName'，因爲'lastName'是一個字段「員工」組件的名稱，感謝這個想法 – Dee

造成的：org.hibernate.QueryException：無法解析屬性：姓氏

回答

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