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這是我第一次使用SpringMVC + Hibernate,所以請原諒我,如果我問一個noob問題。org.hibernate.QueryException:無法解析列名已定義的屬性
而我想要實現的搜索user_tasks屬於一些用戶。所以在UserRepository執行我寫了這個:
@Entity
@Table(name = "usertask")
public class UserTask {
//public enum TaskState {CLAIMED, FINISHED, EXPIRED};
public static int TYPE_CLAIMED = 0;
public static int TYPE_FINISHED = 1;
public static int TYPE_EXPIRED = 2;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Integer id;
@Column(name = "user_id", nullable = false)
private Integer userId;
@Column(name = "task_id", nullable = false)
private Integer taskId;
@Column(name = "curr_usermicrotask_id")
private Integer currUserMicrotaskId;
@Column(name = "state", nullable = false)
private Integer state;
//...some getters and setters
}
另外,我有用戶和任務的類中定義:
@Repository("userTaskRepo")
public class UserTaskRepoImpl extends AbstractDao<Integer, UserTask> implements UserTaskRepository {
public List<UserTask> getByUserId(int userId, int startTaskId, int size) {
List<UserTask> userTasks = getSession().createCriteria(UserTask.class)
.add(Restrictions.eq("user_id", userId))
.add(Restrictions.ge("task_id", startTaskId))
.setMaxResults(size)
.list();
return userTasks;
}
}
和相關UserTask類定義如下。
然而,當我試圖調用該函數在UserTaskRepoImpl 例外
org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.hibernate.QueryException: could not resolve property: user_id of: edu.inlab.models.UserTask
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:979)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:858)
javax.servlet.http.HttpServlet.service(HttpServlet.java:622)
org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:843)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
誰能弄清楚爲什麼會這樣發生錯誤? 在此先感謝!
是它'@Table(名稱= 「usertask」)'?還是應該是@Table(name =「user_tasks」)?你確定表格列被命名爲user_id嗎? – jmcg