不能得到這個井字遊戲玩公平

Question

這是一個tic tac腳趾遊戲與我合作。我原本在學期開始時創建了這個遊戲，但是教練希望我們現在添加一個AI（人工智能），它可以模仿另一個玩家。我採取的最佳方法是製作一個具有隨機數生成器的方法。這對我來說很有效，但是當我運行tic tac toe遊戲時，第二位玩家AI會覆蓋第一位玩家移動。所以爲了防止這種情況發生，我放入了一個條件語句來檢查Jbuttun是否被禁用。但是它不允許我編譯。然後它給出的錯誤是不兼容的類型:(必需的布爾值：找到Void）。

import javax.swing.*; 
import java.awt.*; 
import java.awt.event.*; 
import javax.swing.border.*; 
import java.util.*; 

public class TicTacToe extends JFrame 
{ 
private final int HEIGHT = 450; 
private final int WIDTH = 500; 
private static JButton [] button = new JButton[9]; 
private static Action [] playerTurn = new Action[9]; 
private Font arial = new Font("Arial", Font.BOLD, 20); 
private static int lockButtons = 0; 
private boolean game = false; 
private static Random rNum = new Random(); 



public TicTacToe() 
{ 
    setTitle("TTT"); 
    setSize(HEIGHT, WIDTH); 
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); 


    setLayout(new GridLayout(4,3)); 

    int num = 0; 
    for(int i = 0; i < 9; i++) 
    { 

     button[i] = new JButton("B" + (i + 1)); 
     playerTurn[i] = new Action(); 
     add(button[i]); 
     button[i].setBorder(BorderFactory.createLineBorder(Color.black,10)); 
     button[i].setFont(arial); 
     button[i].addActionListener(playerTurn[i]); 
    } 


    setVisible(true); 
} 

private class Action implements ActionListener 
{ 
    public void actionPerformed(ActionEvent playerMove) 
    { 
     //Get button pressed using GetSource Command 
     JButton whatPlayer=(JButton)(playerMove.getSource()); 

       for (int x =0; x <= button.length; x++) 
       { 
        whatPlayer.setText("o"); 
        whatPlayer.setEnabled(false); 
        validate(); 
        JOptionPane.showMessageDialog(null," Computer's Turn "); 
        player2(); 
        break; 
       } 
    } 

    public void player2() 
    { 
     for (int i = 0; i <= button.length ; i++) 
     { 
        int num = rNum.nextInt(8); 
        button[num].setText("x"); 
        button[num].setEnabled(false); 
        validate(); 

       // This is the block that is causing the compiler error 
       /*if(button[i].setEnabled(false)) 
       { 
        JOptionPane.showMessageDialog(null," Button is disables "); 
        break; 
       }*/ 
        break; 
     }  
    } 

    public void validate() 
    { 
     if(button[0].getText().equals(button[1].getText()) && button[1].getText().equals(button[2].getText())) 
     { 
      JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[0].getText()); 
      gameOver(); 
      return; 
     } 
     else if(button[3].getText().equals(button[4].getText()) && button[4].getText().equals(button[5].getText())) 
     { 
      JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[3].getText()); 
      gameOver(); 
      return; 
     } 
     else if(button[6].getText().equals(button[7].getText()) && button[7].getText().equals(button[8].getText())) 
     { 
      JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[6].getText()); 
      gameOver(); 
      return; 
     } 
     else if(button[0].getText().equals(button[3].getText()) && button[3].getText().equals(button[6].getText())) 
     { 
      JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[0].getText()); 
      gameOver(); 
      return; 
     } 
     else if(button[1].getText().equals(button[4].getText()) && button[4].getText().equals(button[7].getText())) 
     { 
      JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[1].getText()); 
      gameOver(); 
      return; 
     } 
     else if(button[2].getText().equals(button[5].getText()) && button[5].getText().equals(button[8].getText())) 
     { 
      JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[2].getText()); 
      gameOver(); 
      return; 
     } 
     else if(button[0].getText().equals(button[4].getText()) && button[4].getText().equals(button[8].getText())) 
     { 
      JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[0].getText()); 
      gameOver(); 
      return; 
     } 
     else if(button[2].getText().equals(button[4].getText()) && button[4].getText().equals(button[6].getText())) 
     { 
      JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[2].getText()); 
      gameOver(); 
      return; 
     } 

     int i; 

     for(i=0;i<button.length;i++) 
     { 
      if(button[i].isEnabled()) 
      { 
       break; 
      } 
     } 
     if(i == button.length) 
     { 
      JOptionPane.showMessageDialog(null,"This was a Draw"); 
     } 
    } 
    public void gameOver() 
    { 
     for(int x = 0; x < button.length; x++) 
     { 
      button[x].setEnabled(false); 
     } 
    } 
} 
public static void main(String[] arg) 
{ 
    new TicTacToe(); 
} 
} 

Answer 1

if(button[i].setEnabled(false)) 
{ 
    JOptionPane.showMessageDialog(null," Button is disables "); 
    break; 
} 

你確實試圖檢查條件語句中的void類型，這是不能做到的。 由於setEnabled返回void（無）。 什麼，你應該做的是檢查的「已啓用」 getter方法，所以：

if (!button[i].isEnabled()) { 
    JOptionPane.showMessageDialog(null," Button is disables "); 
    break; 
} 

注意「！」在聲明之前，這使得它爲負

Answer 2

if(button[i].setEnabled(false)) 
{ 
    JOptionPane.showMessageDialog(null," Button is disables "); 
    break; 
} 

setEnabled()返回void，這就是爲什麼它給你的錯誤，也許你的意思是.isEnabled()？如果按鈕被啓用，否則爲false禁用

if(!button[i].isEnabled()) 
{ 
    JOptionPane.showMessageDialog(null," Button is disables "); 
    break; 
} 

isEnabled()返回true。