2017-01-03 38 views
1

我得到了從論壇向缺陷套件添加缺陷的代碼片段。 但是,我的要求是從缺陷套件中提取缺陷,並且我不知道缺陷套件信息。來自工作區的拉力拉動缺陷套件

有沒有辦法從中收集缺陷套件和缺陷。

以下是將缺陷添加到缺陷套件的示例代碼片段。

> import com.google.gson.JsonArray; 
import com.google.gson.JsonObject; 
import com.rallydev.rest.RallyRestApi; 
import com.rallydev.rest.request.CreateRequest; 
import com.rallydev.rest.request.QueryRequest; 
import com.rallydev.rest.request.UpdateRequest; 
import com.rallydev.rest.response.CreateResponse; 
import com.rallydev.rest.response.QueryResponse; 
import com.rallydev.rest.response.UpdateResponse; 
import com.rallydev.rest.util.Fetch; 
import com.rallydev.rest.util.QueryFilter; 
import com.rallydev.rest.util.Ref; 

import java.io.IOException; 
import java.net.URI; 
import java.net.URISyntaxException; 

public class addDefectToSuite { 

    public static void main(String[] args) throws URISyntaxException, IOException { 

     String host = "https://rally1.rallydev.com"; 
      String username = "[email protected]ompany.com"; 
      String password = "secret"; 
      String wsapiVersion = "v2.0"; 
      String projectRef = "/project/12352608219";  
      String workspaceRef = "/workspace/12352608129"; 
      String applicationName = "Create defect, add to a defectsuite"; 


     RallyRestApi restApi = new RallyRestApi(
       new URI(host), 
       username, 
       password); 
     restApi.setWsapiVersion(wsapiVersion); 
     restApi.setApplicationName(applicationName); 

     QueryRequest defectSuiteRequest = new QueryRequest("DefectSuite"); 
     defectSuiteRequest.setFetch(new Fetch("FormattedID","Name", "Defects")); 
     defectSuiteRequest.setWorkspace(workspaceRef); 
     defectSuiteRequest.setQueryFilter(new QueryFilter("FormattedID", "=", "DS1")); 
     QueryResponse defectSuiteQueryResponse = restApi.query(defectSuiteRequest); 
     JsonObject defectSuiteJsonObject = defectSuiteQueryResponse.getResults().get(0).getAsJsonObject(); 
     System.out.println("defectSuiteJsonObject" + defectSuiteJsonObject); 
     String defectSuiteRef = defectSuiteJsonObject.get("_ref").getAsString(); 
     int numberOfDefects = defectSuiteJsonObject.getAsJsonObject("Defects").get("Count").getAsInt(); 
     System.out.println(defectSuiteJsonObject.get("Name") + " ref: " + defectSuiteRef + "number of defects: " + numberOfDefects + " " + defectSuiteJsonObject.get("Defects")); 


     try { 
      JsonObject defect = new JsonObject(); 
      defect.addProperty("Name", "bad defect 668"); 

      CreateRequest createRequest = new CreateRequest("defect", defect); 
      CreateResponse createResponse = restApi.create(createRequest); 
      if (createResponse.wasSuccessful()) { 
       JsonObject defectJsonObject = createResponse.getObject(); 
       String defectRef = Ref.getRelativeRef(createResponse.getObject().get("_ref").getAsString()); 
       System.out.println(String.format("Created %s", defectRef)); 
       JsonObject defectSuitesOfThisDefect = (JsonObject) defectJsonObject.get("DefectSuites"); 
       int numberOfSuites = defectSuitesOfThisDefect.get("Count").getAsInt(); 
       System.out.println("number of defect suites this defect is part of: " + numberOfSuites); 
       QueryRequest defectSuitesOfThisDefectRequest = new QueryRequest(defectSuitesOfThisDefect); 
       JsonArray suites = restApi.query(defectSuitesOfThisDefectRequest).getResults(); 
       System.out.println("suites: " + suites); 
       suites.add(defectSuiteJsonObject); 
       System.out.println("suites after add: " + suites); 
       //Update defect: add to defectsutites collection 
       JsonObject defectUpdate = new JsonObject(); 
       defectUpdate.add("DefectSuites", suites); 
       UpdateRequest updateDefectRequest = new UpdateRequest(defectRef,defectUpdate); 
       UpdateResponse updateResponse = restApi.update(updateDefectRequest); 
       if (updateResponse.wasSuccessful()) { 
        System.out.println("Successfully updated defect: " + defectJsonObject.get("FormattedID")); 
       } 
       else { 
        String[] updateErrors; 
        updateErrors = createResponse.getErrors(); 
        System.out.println("Error"); 
        for (int i=0; i<updateErrors.length;i++) { 
         System.out.println(updateErrors[i]); 
        } 
       } 

      } else { 
       System.out.println("error"); 
      } 

     } finally { 
      restApi.close(); 
     } 

    } 
} 
+0

我很難理解你到底想要做什麼。上面的代碼可以工作,但通過集合修改端點確實有一個更簡單的方法。您是否需要在特定缺陷套件下創建缺陷?或者你只是想在現有的缺陷套件下加載缺陷集合? –

+0

嗨凱爾,感謝您的迴應,我只想加載現有缺陷套件下的缺陷集合 –

回答

0

缺陷對象有一個DefectSuites集合,所以你可以只查詢其中DefectSuites包含您指定的DefectSuite所有缺陷:

QueryRequest defectsRequest = new QueryRequest("Defect"); 
defectsRequest.setFetch(new Fetch("FormattedID","Name")); 
defectsRequest.setQueryFilter(new QueryFilter("DefectSuites", "contains", defectSuiteRef)); 
QueryResponse defectsResponse = restApi.query(defectsRequest); 

或者,您可以通過查詢來它從另一條路直接在您的DefectSuite上的原始代碼中的Defects集合:

JsonObject defectsCollection = defectSuiteJsonObject.getAsJsonObject("Defects"); 
QueryRequest defectsRequest = new QueryRequest(defectsCollection); 
defectSuiteRequest.setFetch(new Fetch("FormattedID","Name")); 
QueryResponse defectsResponse = restApi.query(defectsRequest);