SQL：如何確保即使並非全部都被執行，所有SELECT個案都被表示？

Question

這裏是我的代碼

SELECT 
    CASE 
     WHEN Money >= 20000 THEN '$ 20,000 + ' 
     WHEN Money BETWEEN 10000 AND 19999 THEN '$ 10,000 - $ 19,999' 
     WHEN Money BETWEEN 5000 AND 9999 THEN '$ 5,000 - $ 9,999' 
     WHEN Money BETWEEN  1 AND 4999 THEN '$  1 - $ 4,999' 
     ELSE '$  0' 
    END AS [MONEY], 
     COUNT(*) AS [#], 
     MAX(Money) AS [MAX] 
    FROM MyTable 
WHERE MoneyType = 'Type A' 
GROUP BY 
    CASE 
     WHEN Money >= 20000 THEN '$ 20,000 + ' 
     WHEN Money BETWEEN 10000 AND 19999 THEN '$ 10,000 - $ 19,999' 
     WHEN Money BETWEEN 5000 AND 9999 THEN '$ 5,000 - $ 9,999' 
     WHEN Money BETWEEN  1 AND 4999 THEN '$  1 - $ 4,999' 
     ELSE '$  0' 
    END 
ORDER BY MAX DESC 

現在我的問題是，我希望所有的情況下，以顯示我的結果集中的行，但是，因爲我沒有將在該行不1和4999之間的下降的任何值出現。我仍然希望該行顯示，並且只包含0的列（當然除了第一個）。任何人都可以告訴我如何修改代碼來完成此操作？也許我需要以不同的方式去做...謝謝！結果集的

例子我找...

| [MONEY]    | [#] | [MAX] | 
    | $ 20,000+   | 2  | 30,000 | 
    | $ 10,000 - $ 19,999 | 8  | 19,000 | 
    | $ 5,000 - $ 9,999 | 4  |  8,000 | 
    | $  1 - $ 4,999 | 0  |  0  |  <-- Row currently doesn't show 
    | $  0    | 12 |  0  | 

Answer 1

你可以建立一個查詢一個CTE表，然後用它來分組，而不是Case語句。您需要進行其他三項更改

• COUNT將需要爲COUNT（t.Money），否則當您期待零時，您會得到1。
• 您可能希望合併您的MAX（金錢），但我不確定當它的NULL爲空時您想要的是什麼
• 您實際上無法按MAX（MONEY）排序，因爲它可能爲空。因此，它能夠更好地使用CTE來控制順序以及

WITH Ranges AS 
(SELECT 1 id , '$ 20,000 +' description 
    UNION SELECT 2 , '$ 10,000 - $19,999' 
    UNION SELECT 3, '$ 5,000 - $ 9,999' 
    UNION SELECT 4, '$  1 - $ 4,999' 
    UNION SELECT 5, '$  0') 


SELECT 
     r.Description as money, 
     COUNT(t.Money) AS [#], 
     MAX(Money) AS [MAX] 
    FROM 
     Ranges r 
     LEFT JOIN 
     MyTable t 
     ON r.ID = CASE 
        WHEN Money >= 20000 THEN 1 
        WHEN Money BETWEEN 10000 AND 19999 THEN 2 
        WHEN Money BETWEEN 5000 AND 9999 THEN 3 
        WHEN Money BETWEEN  1 AND 4999 THEN 4 
        ELSE 5 
       END 
     AND MoneyType = 'Type A' 
GROUP BY 
    r.id, 
    r.Description 
ORDER BY r.id asc 

LIVE DEMO

Answer 2

您可以添加值，然後將另外一組（沒有獲得SSMS測試）：

SELECT [MONEY], SUM([#]) AS [#], MAX([MAX]) AS [MAX] FROM 
(SELECT 
    CASE 
     WHEN Money >= 20000 THEN '$ 20,000 + ' 
     WHEN Money BETWEEN 10000 AND 19999 THEN '$ 10,000 - $19,999' 
     WHEN Money BETWEEN 5000 AND 9999 THEN '$ 5,000 - $ 9,999' 
     WHEN Money BETWEEN  1 AND 4999 THEN '$  1 - $ 4,999' 
     ELSE '$  0' 
    END AS [MONEY], 
     COUNT(*) AS [#], 
     MAX(Money) AS [MAX] 
    FROM MyTable 
WHERE MoneyType = 'Type A' 
GROUP BY 
    CASE 
     WHEN Money >= 20000 THEN '$ 20,000 + ' 
     WHEN Money BETWEEN 10000 AND 19999 THEN '$ 10,000 - $19,999' 
     WHEN Money BETWEEN 5000 AND 9999 THEN '$ 5,000 - $ 9,999' 
     WHEN Money BETWEEN  1 AND 4999 THEN '$  1 - $ 4,999' 
     ELSE '$  0' 
    END 
UNION ALL 
SELECT '$  0' AS [MONEY], 0 AS [#], 0 AS [MAX] 
UNION ALL 
SELECT '$  1 - $ 4,999' AS [MONEY], 0 AS [#], 0 AS [MAX] 
UNION ALL 
SELECT '$ 5,000 - $ 9,999' AS [MONEY], 0 AS [#], 0 AS [MAX] 
UNION ALL 
SELECT '$ 10,000 - $19,999' AS [MONEY], 0 AS [#], 0 AS [MAX] 
UNION ALL 
SELECT '$ 20,000 + ' AS [MONEY], 0 AS [#], 0 AS [MAX] 
) SUB 
GROUP BY [MONEY] 

Answer 3

嗯......我會怎麼做：

而不是 從 表T

我從子查詢

From 
(
Select Money, 1 as ForReal from Table t 
Union 
Select 1, 0 
Union 
Select 5000, 0 
Union 
Select 10000, 0 
Union 
Select 20001, 0 
) 

選擇我的頂部選擇將 最大（獎金* ForReal），讓您得到您的分組和0作爲MaxAmount ..

Answer 4

您可以在描述性文本存儲在一個真實的或臨時表&相應的加盟，像;

;with ranges(min,max,caption) as (
    select 10000, 19999, '$ 10,000 - $19,999' union 
    select 5000, 9999, '$ 5,000 - $ 9,999' union 
    select 1, 4999,  '$  1 - $ 4,999' 
) 
select 
    isnull(r.caption, 'no description'), 
    count(m.money) as [#], 
    isnull(max(m.money), 0) 
from 
    mytable m 
full outer join 
    ranges r on m.money between r.min and r.max 
group by 
    r.caption