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Question

相同的值合併陣列我使用PHP 水珠功能在子目錄獲取圖像，我不知道有多少文件在每個目錄

目錄名是id存在的，我要分類的所有圖像目錄在一個陣列

$arr = []; 
$dir = dirname(__FILE__)."/gulets"; 
$files = glob($dir."/*/*_gulet_o_*"); 
foreach ($files as $file) { 
    $fullname = str_replace($dir."/", "", $file); 
    $name = explode("/", $fullname); 
    $name1 = array('id'=>$name[0],'name'=>$name[1]); 
    $arr[] = $name1; 
} 
header('Content-Type: application/json'); 
echo json_encode($arr); 

[ 
{ 
"id": "10", 
"name": "asdsad_gulet_o_1.jpg" 
}, 
{ 
"id": "10", 
"name": "wqes_gulet_o_10.jpg" 
}, 
{ 
"id": "10", 
"name": "qwsdf_gulet_o_11.jpg" 
}, 
{ 
"id": "10", 
"name": "sdce_gulet_o_12.jpg" 
}, 
{ 
"id": "11", 
"name": "fsdsc_gulet_o_13.jpg" 
}, 
{ 
"id": "11", 
"name": "drfvc_gulet_o_14.jpg" 
}, 
{ 
"id": "12", 
"name": "dsyjhk_gulet_o_15.jpg" 
}, 
. 
. 

，我需要改變這樣的：

[ 
    { 
    "id": "10", 
    "name1": "asdsad_gulet_o_1.jpg", 
    "name2": "wqes_gulet_o_10.jpg", 
    "name3": "qwsdf_gulet_o_11.jpg" 
    "name4": "sdce_gulet_o_12.jpg" 
    }, 
    { 
    "id": "11", 
    "name1": "fsdsc_gulet_o_13.jpg" 
    "name2": "drfvc_gulet_o_14.jpg" 
    }, 
    { 
    "id": "12", 
    "name1": "dsyjhk_gulet_o_15.jpg" 
. 
. 

Answer 1

我認爲創建索引像name1,name2，name3等沒有用。你應該創建索引names的子數組，並在那裏放上你的名字。嘗試這樣的代碼：

<?php 

$array = array(
    array('id'=>1, 'name'=>'qwerty'), 
    array('id'=>2, 'name'=>'asdf'), 
    array('id'=>2, 'name'=>'hjkl'), 
    array('id'=>1, 'name'=>'cvbnm'), 
    array('id'=>1, 'name'=>'yuiop'), 
); 

$groups = array(); 

foreach($array as $singleRow) 
{ 
    if(!isset($groups[$singleRow['id']])) 
     $groups[$singleRow['id']] = array('id'=>$singleRow['id'], 'names'=>array()); 

    $groups[$singleRow['id']]['names'][] = $singleRow['name']; 
} 
$json = json_encode(array_values($groups));  
var_dump($json); 

它輸出：

[{"id":1,"names":["qwerty","cvbnm","yuiop"]},{"id":2,"names":["asdf","hjkl"]}] 

Answer 2

代替 -

$name1 = array('id'=>$name[0],'name'=>$name[1]); 
$arr[] = $name1; 

，你可以使用類似 -

$nameKey = 'name' . $name[0]; 
$name1 = array('id'=>$name[0],$nameKey =>$name[1]); 
if (!empty($arr[$name[0]])) { 
    $arr[$name[0]] = $arr[$name[0]] + $name1; 
} 
else { 
    $arr[$name[0]] = $name1; 
} 

和foreach結束後（）循環做 -

$arr = array_values($arr); 

Answer 3

你想是這樣的：

foreach ($arr as $a) { 
    $new_arr[$a['id']]['names'][] = $a['name']; 
}