使用javascript創建強密碼

Question

我有一個如下的函數，它創建一個強密碼，但它並不總是添加一個特殊字符和一個數字或大寫字母給它，我如何確保它始終具有這些包含在它的要求。

密碼要求很長，它已經

8個或更多字符，並且必須有一個特殊的字符， 大寫字母，其中包括一個編號。

我已經把現在顯示以下功能

function GenPwd(nMinimumLength,bIsRequired,sNameoftheButton){ 
      var end=0; 
      var index=0; 
      var sPassCharactersWithoutSpeacil="!#$@*123456789aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ"; 
      var sSpecialCharacters="!#$@*"; 
      var nSrngLen=sStrgStrAddOnChrs 
      var sNumbers="123456789"; 
      var nMinimunLen=Math.round(nBaseLen/2); 
      var PassWordDLength=Math.round((Math.random()*nMinLen)+nMinimumLength+nMinimumLength); //Make sure it is atleadt 8 characters long 
      var Password=""; 
      var PasswordTemporary=""; 
      for(index = 1; index <= PassWordDLength; index++) { 

       nCharacter = Math.round(Math.random()*65); 

       PasswordTemporary = sPassCharactersWithoutSpeacil.charAt(nCharacter); 

       while (PWD.indexOf(PasswordTemporary) > -1) { 
        nCharacter = ''; 
        nCharacter = Math.round(Math.random()*65); 
        PasswordTemporary = sPassCharactersWithoutSpeacil.charAt(nChar); 
       } 
       FinalPWD = Password + PasswordTemporary; 
      } 

這是我必須使用

function GenPwd(nBaseLen,bIsStrong,sBtnName){ 

     var end=0; 
     var index=0; 
     var sPassStr="!#$@*123456789aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ"; 
     var sStrgStrAddOnChrs="!#$@*"; 
     var nSrngLen=sStrgStrAddOnChrs 
     var sStrgStrAddOnNum="123456789"; 
     var nMinLen=Math.round(nBaseLen/2); 
     var PWDLen=Math.round((Math.random()*nMinLen)+nBaseLen); 
     var PWD=""; 
     var PWDTmp=""; 
     //Generate the password 
     for(index = 1; index <= PWDLen; index++) { 

      nChar = Math.round(Math.random()*65); 

      PWDTmp = sPassStr.charAt(nChar); 

      while (PWD.indexOf(PWDTmp) > -1) { 
       nChar = ''; 
       nChar = Math.round(Math.random()*65); 
       PWDTmp = sPassStr.charAt(nChar); 
      } 
      PWD = PWD + PWDTmp; 
     } 

      document.getElementById("pwd").value=PWD; 
     EnableBtn(sBtnName); 
     return true; 
    } 

Answer 1

您可以創建，以確保您的PWD包含至少一個功能一組特定的字符：

function ensurePwdContains(pwd, regexListOfChars, listOfChars) { 
    if (!regexListOfChars.test(pwd)) { 
     // select random char from listOfChars 
     var newChar = listOfChars.charAt(Math.floor(Math.random() * listOfChars.length)); 

     // insert it into the current pwd in a random location 
     // must do +1 to include the location at the end of the string 
     var pos = Math.floor(Math.random() * (pwd.length + 1)); 
     pwd = pwd.slice(0, pos) + newChar + pwd.slice(pos); 
    } 
    return pwd; 
} 

此函數將測試以查看密碼是否至少包含一個傳入的正則表達式實例。如果不是，將從listOfChars參數中選擇一個隨機字符，然後將其插入隨機位置中的現有密碼。

而且，然後調用這個函數在你的函數結束您的每個兩種情況：

FinalPwd = ensurePwdContains(FinalPwd, /[!#\$@*]/, sSpecialCharacters); 
FinalPwd = ensurePwdContains(FinalPwd, /[A-Z]/, "ABCDEFGHIJKLMNOPQRSTUWXYZ"); 

演示：http://jsfiddle.net/jfriend00/ur9FL/

---

而且，這裏的清理版本的整體實施。你指的是你的函數中的一些變量，它們或者沒有在你的文章中定義，或者沒有在你的函數中使用，所以我刪除了這些變量（因爲我不知道它們是什麼或它們是如何使用的）。這是一個有點清潔執行：

function generatePwd(minLen) { 
    // create a pwd that is between minLen and ((2 * minLen) + 2) long 
    // don't repeat any characters 
    // require at least one special char and one capital char 
    function rand(max) { 
     return Math.floor(Math.random() * max); 
    } 

    function ensurePwdContains(pwd, regexListOfChars, listOfChars) { 
     if (!regexListOfChars.test(pwd)) { 
      var newChar = listOfChars.charAt(rand(listOfChars.length)); 
      var pos = rand(pwd.length + 1); 
      pwd = pwd.slice(0, pos) + newChar + pwd.slice(pos); 
     } 
     return pwd; 
    } 

    var legalChars = "!#$@*123456789aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ"; 
    var specialChars = "!#$@*"; 
    var specialRegex = /[!#\$@*]/; 
    var caps = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; 
    var capsRegex = /[A-Z]/; 
    var nums = "123456789"; 
    var numRegex = /[1-9]/; 

    // make legalChars into an array of chars (easier to deal with) 
    legalChars = legalChars.split(""); 
    var pwd = "", len = minLen + rand(minLen), index; 

    // ensure len is not too long 
    len = Math.min(legalChars.length, len); 

    // now add chars to the pwd string until it is of the desired length 
    while (pwd.length < len) { 
     index = rand(legalChars.length); 
     pwd += legalChars[index]; 
     // remove the char we just used 
     legalChars.splice(index, 1); 
    } 
    // ensure we have at least one special character and one caps char and one 1-9 
    pwd = ensurePwdContains(pwd, specialRegex, specialChars); 
    pwd = ensurePwdContains(pwd, capsRegex, caps); 
    pwd = ensurePwdContains(pwd, numRegex, nums); 
    return pwd;  
} 

而且，產生一大堆密碼的，所以你可以看到你得到什麼類型變化的工作演示：http://jsfiddle.net/jfriend00/7dReY/

---

爲了把密碼到位，我建議你做第二個函數，調用第一個函數來生成密碼並將其放入選擇的字段中：

function putPasswordInPlace(pwdId, sBtnName) { 
    var pwd = generatePwd(8); 
    document.getElementById(pwdId).value = pwd; 
    EnableButton(sBtnName); 
}