MySQL的計數和group by

Question

天

我有以下結構

ID DATE(DATETIME)   TID 
1  2012-04-01 23:23:23 8882 

我想在每個月的每一天匹配TID = 8882

感謝數行，他們團的量

Answer 1

您可以使用DAY功能組：

SELECT DAY(Date), COUNT(*) 
FROM table 
WHERE TID = 8882 
GROUP BY DAY(Date) 

Answer 2

試試這個：

SELECT DAY(date) AS `DAY`, COUNT(1) AS `COUNT` FROM 
table1 
    WHERE TID = 8882 
GROUP BY DAY(date) 

什麼MySQL Query GROUP BY day/month/year

Answer 3

不知道到底你在當月的一天是什麼意思 - 你想組二月與3月1日第一次？或者你只是說日期？假如是後者，這個怎麼樣：

SELECT DATE(date) as d,count(ID) from TABLENAME where TID=8882 GROUP by d; 

Answer 4

嘗試此查詢：

SELECT COUNT(id), DAY(dat), MONTH(dat), YEAR(dat) 
FROM table 
WHERE TID=8882 
GROUP BY YEAR(dat), MONTH(dat), DAY(dat);