4
爲了成爲一個更好的腳本編寫者,有沒有辦法讓下面的代碼少用幾行?perl高效代碼
sub task1_2_2 {
#Make sure syslog configuration is correct
my @r3r = my @r4r = my @r5r = my @r6r = my @r7r = my @r8r = ("name = 67.176.10.200","facility-override = local3");
my @r1r = ("name = 67.176.10.200","facility-override = local3","source-address = 67.176.255.1");
my @r2r = ("name = 67.176.10.200","facility-override = local3","source-address = 67.176.255.2");
my (@r1,@r2,@r3,@r4,@r5,@r6,@r7,@r8,%seen,@result1,@result2,@result3,@result4,@result5,@result6,@result7,@result8,$results,$item,$ii);
my $pass = "pass";
my $xinfo = shift;
my $ip = shift;
my $data = XML::LibXML->load_xml(string => $xinfo);
my $datax = XML::LibXML::XPathContext->new($data);
my $syspath = '/configuration/system/syslog/host/*';
foreach ($datax->findnodes($syspath)) {
if($ip eq "67.176.10.2" && $_->getName() ne "contents") {my $v = join " = ",$_->getName(),$_->to_literal;push @r1,$v};
if($ip eq "67.176.10.3" && $_->getName() ne "contents") {my $v = join " = ",$_->getName(),$_->to_literal;push @r2,$v};
if($ip eq "67.176.10.4" && $_->getName() ne "contents") {my $v = join " = ",$_->getName(),$_->to_literal;push @r3,$v};
if($ip eq "67.176.10.5" && $_->getName() ne "contents") {my $v = join " = ",$_->getName(),$_->to_literal;push @r4,$v};
if($ip eq "67.176.10.6" && $_->getName() ne "contents") {my $v = join " = ",$_->getName(),$_->to_literal;push @r5,$v};
if($ip eq "67.176.10.7" && $_->getName() ne "contents") {my $v = join " = ",$_->getName(),$_->to_literal;push @r6,$v};
if($ip eq "67.176.10.8" && $_->getName() ne "contents") {my $v = join " = ",$_->getName(),$_->to_literal;push @r7,$v};
if($ip eq "67.176.10.9" && $_->getName() ne "contents") {my $v = join " = ",$_->getName(),$_->to_literal;push @r8,$v};
}
@seen{@r1} = (); if($ip eq "67.176.10.2") {foreach $item (@r1r) { push(@result1, $item) unless exists $seen{$item}; }}
if(@result1) {
foreach $ii (@result1) {$results .= "On R1 Syslog $ii ,is either missing or incorrect configuration was done\n";}
}
%seen=();
$item=$ii = undef;
@seen{@r2} = (); if($ip eq "67.176.10.3") {foreach $item (@r2r) { push(@result2, $item) unless exists $seen{$item}; }}
if(@result2) {
foreach $ii (@result2) {$results .= "On R2 Syslog $ii ,is either missing or incorrect configuration was done\n";}
}
%seen=();
$item=$ii = undef;
@seen{@r3} = (); if($ip eq "67.176.10.4") {foreach $item (@r3r) { push(@result3, $item) unless exists $seen{$item}; }}
if(@result3) {
foreach $ii (@result3) {$results .= "On R3 Syslog $ii ,is either missing or incorrect configuration was done\n";}
}
%seen=();
$item=$ii = undef;
@seen{@r4} = (); if($ip eq "67.176.10.5") {foreach $item (@r4r) { push(@result4, $item) unless exists $seen{$item}; }}
if(@result4) {
foreach $ii (@result4) {$results .= "On R4 Syslog $ii ,is either missing or incorrect configuration was done\n";}
}
%seen=();
$item=$ii = undef;
@seen{@r5} = (); if($ip eq "67.176.10.6") {foreach $item (@r5r) { push(@result5, $item) unless exists $seen{$item}; }}
if(@result5) {
foreach $ii (@result5) {$results .= "On R5 Syslog $ii ,is either missing or incorrect configuration was done\n";}
}
%seen=();
$item=$ii = undef;
@seen{@r6} = (); if($ip eq "67.176.10.7") {foreach $item (@r6r) { push(@result6, $item) unless exists $seen{$item}; }}
if(@result6) {
foreach $ii (@result6) {$results .= "On R6 Syslog $ii ,is either missing or incorrect configuration was done\n";}
}
%seen=();
$item=$ii = undef;
@seen{@r7} = (); if($ip eq "67.176.10.8") {foreach $item (@r7r) { push(@result7, $item) unless exists $seen{$item}; }}
if(@result7) {
foreach $ii (@result7) {$results .= "On R7 Syslog $ii ,is either missing or incorrect configuration was done\n";}
}
%seen=();
$item=$ii = undef;
@seen{@r8} = (); if($ip eq "67.176.10.9") {foreach $item (@r8r) { push(@result8, $item) unless exists $seen{$item}; }}
if(@result8) {
foreach $ii (@result8) {$results .= "On R8 Syslog $ii ,is either missing or incorrect configuration was done\n";}
}
if($results) { return $results; } elsif(!$results) { return $pass }
}
我將會寫很多這些子程序。 基本上我通過一個路由器循環運行這個子程序,如果有什麼東西不符合我的期望我想返回什麼路由器是不正確的,缺少什麼。代碼的工作原理,但它感覺非常冗長,因爲我沒有編寫很長的代碼。 在此先感謝您的任何反饋意見。
我知道引用是要走的路,只是以前從未使用過它們,並閱讀了我沒有上下文的文檔,因此我無法用我的項目對其進行可視化。感謝您的解決方案,我會盡力回覆。 – salparadise
您可能會發現[perlreftut](http://perldoc.perl.org/perlreftut.html)更好的引用介紹。 –
@格蘭特麥克萊恩:謝謝,我忘了那一個:-( –