實現3維稀疏表的構造函數

Question

有一個名爲「約會」的類，其中3個對象需要定義。

這是怎麼類最初給出：

/*You must complete this class such that it can be used as nodes in a 3D sparse table.*/ 
public class Appointment 
{ 
    public Appointment() 
    { 
    /*You may implement this constructor to suit your needs, or you may add additional constructors.*/ 
    } 

    public Appointment back;//The next appointment (back) of this appointment on the same date 
    public Appointment right;//The next appointment (right) of this appointment in the same week. 
    public Appointment down;//The next appointment (down) of this appointment in the same month. 

    //Appointment particulars: 
    private String description;//A description for this appointment. 
    private int duration;//The number of hours that the appointment will last. 
} 

還有其他功能，這並不重要。

所以我的想法是創建一個新的方法來初始化每個對象（不確定是不是我的權利！）

public Appointment() 
{ 

     right.appointmentRight(); 
} 

    public void appointmentRight() 
    { 
     for(int i=0; i<12; i++) 
     { 
     right = new Appointment(); //trying to initialize them for 12 months 

     } 
    } 

誰能給我解釋一下，如果我在正確的軌道很，或者我必須做一些完全不同的事情 謝謝

Answer 1

我看到的第一件事是當你調用'right.appointmentRight（）;'對象'right'尚未初始化。

但是，如果你初始化它，你會有一些麻煩。你構造函數調用一個名爲appointmentRight（）的函數，它調用構造函數，調用appointmentRight（）...是的，無限循環。另外，在FOR循環的每次迭代中，都會擦除舊的「正確」值。

您可以添加一些其它附加的構造類似以下：

public Appointment(Appointment back) { 
    this.back = back; 
} 

根據您的問題，您也可以有更多有具體的構造函數，如：

public Appointment(Appointment back, boolean isRight, boolean isDown) { 
    this.back = back; 
    if (isRight) 
     back.setRight(this); 
    if (isDown) 
     back.setDown(this); 
} 

private void setRight(Appointment right) { 
    this.right = right; 
} 

private void setDown(Appointment down) { 
    this.down = down; 
}