查找匹配或不匹配的兩個表

Question

我是新來的sql所以讓我道歉，我開始之前之間。

我試圖國旗我會撥打以下方式保單號碼相匹配。

Select c.last_name, c.first_name, c.sex, c.date_of_birth, c.record_nbr, 
case when ph.policy_nbr = cp.policy_nbr then ph.policy_nbr else 'No Match' 

From table ph 

Left join client c 
On ph.last_name = c.last_name 
And ph.first_name = c.first_name 
And ph.date_of_birth = c.date_of_birth 
And ph.sex = c.sex 
Left join person_payer cp 
On c.person_id = cp.person_id 

Group by c.last_name, c.first_name,c.date_of_birth, 
c.sex,ph.policy_num, cp.policy_nbr 

這個想法是根據姓氏，名字，dob和性別找到匹配表。然後我想驗證一個保單號上的匹配或不匹配。患者記錄中是否存在保單編號？不幸的是，由於客戶記錄中存在多個保單編號，因此這會產生匹配並且不匹配。我如何才能在報告列表中列出客戶一次且僅列出「不匹配」或匹配保單編號。

Answer 1

假設策略表的名字是PolicyTable（因爲它的命名錶，但SQL Server的抱怨吧），你可以做選擇的單柱，而不是加入。

Select c.last_name, c.first_name, c.sex, c.date_of_birth, c.record_nbr, 
ISNULL((Select top 1 ph.policy_nbr from PolicyTable ph where ph.last_name = c.last_name 
And ph.first_name = c.first_name 
And ph.date_of_birth = c.date_of_birth 
And ph.sex = c.sex 
And cp.policy_nbr = ph.policy_nbr), 'No Match') as PolicyNumber 

From client c 
Left join person_payer cp On c.person_id = cp.person_id 

Answer 2

Select c.last_name, c.first_name, c.sex, c.date_of_birth, c.record_nbr, 
isnull(cp.policy_nbr, 'No Match') 

From table ph 

Left join client c 
On ph.last_name = c.last_name 
And ph.first_name = c.first_name 
And ph.date_of_birth = c.date_of_birth 
And ph.sex = c.sex 
Left join person_payer cp 
On c.person_id = cp.person_id 
and ph.policy_nbr = cp.policy_nbr 

Group by c.last_name, c.first_name,c.date_of_birth, 
c.sex,ph.policy_num, cp.policy_nbr