我正在嘗試C++中哈希表實現的以下代碼。程序編譯並接受輸入,然後出現一個彈出窗口,提示「項目已停止工作,Windows正在檢查問題的解決方案,我覺得程序正在某個地方的無限循環中,任何人都可以發現錯誤。 !C++中的哈希表實現
#include <iostream>
#include <stdlib.h>
#include <string>
#include <sstream>
using namespace std;
/* Definitions as shown */
typedef struct CellType* Position;
typedef int ElementType;
struct CellType{
ElementType value;
Position next;
};
/* *** Implements a List ADT with necessary functions.
You may make use of these functions (need not use all) to implement your HashTable ADT */
class List{
private:
Position listHead;
int count;
public:
//Initializes the number of nodes in the list
void setCount(int num){
count = num;
}
//Creates an empty list
void makeEmptyList(){
listHead = new CellType;
listHead->next = NULL;
}
//Inserts an element after Position p
int insertList(ElementType data, Position p){
Position temp;
temp = p->next;
p->next = new CellType;
p->next->next = temp;
p->next->value = data;
return ++count;
}
//Returns pointer to the last node
Position end(){
Position p;
p = listHead;
while (p->next != NULL){
p = p->next;
}
return p;
}
//Returns number of elements in the list
int getCount(){
return count;
}
};
class HashTable{
private:
List bucket[10];
int bucketIndex;
int numElemBucket;
Position posInsert;
string collision;
bool reportCol; //Helps to print a NO for no collisions
public:
HashTable(){ //constructor
int i;
for (i=0;i<10;i++){
bucket[i].setCount(0);
}
collision = "";
reportCol = false;
}
int insert(int data){
bucketIndex=data%10;
int col;
if(posInsert->next==NULL)
bucket[bucketIndex].insertList(data,posInsert);
else { while(posInsert->next != NULL){
posInsert=posInsert->next;
}
bucket[bucketIndex].insertList(data,posInsert);
reportCol=true;}
if (reportCol==true) col=1;
else col=0;
numElemBucket++;
return col ;
/*code to insert data into
hash table and report collision*/
}
void listCollision(int pos){
cout<< "("<< pos<< "," << bucketIndex << "," << numElemBucket << ")"; /*codeto generate a properly formatted
string to report multiple collisions*/
}
void printCollision();
};
int main(){
HashTable ht;
int i, data;
for (i=0;i<10;i++){
cin>>data;
int abc= ht.insert(data);
if(abc==1){
ht.listCollision(i);/* code to call insert function of HashTable ADT and if there is a collision, use listCollision to generate the list of collisions*/
}
//Prints the concatenated collision list
ht.printCollision();
}}
void HashTable::printCollision(){
if (reportCol == false)
cout <<"NO";
else
cout<<collision;
}
程序的輸出是那裏是在哈希表的碰撞,thecorresponding桶數目,並在該區塊的元素數量的點。
也許你應該做一些調試,看看哪個循環它卡在?這聽起來像你正在使用Visual Studio,這意味着你可以通過你的代碼,直到它卡住... –
你已經''10'撒在你的代碼在這裏。難道這不是最起碼的常數嗎?此外,使用素數作爲您的存儲桶大小通常是一個好主意。 – tadman