我收到此錯誤與下面的SQL:SQL錯誤512,同時使SQL作業
子查詢返回多個值。當子查詢遵循=,!=,<,< =,>,> =或當子查詢用作表達式時,這是不允許的。
有人知道我該如何解決嗎?
use character
DECLARE @guild_codex varchar(25)
DECLARE @character_name0 varchar(40)
DECLARE @user_no0 varchar (25), @id varchar (25)
DECLARE @user_no varchar (25), @group_id varchar (25), @amount varchar (25)
DECLARE @free_amount varchar(25), @2mx_Leader varchar(3), @2mx_member varchar (3)
SET @2mx_Leader = 700 SET @2mx_member = 500 SET @id = (SELECT id from
[PC-ID].[Cash].[dbo].[user_cash] where free_amount LIKE 0) SET
@user_no = (SELECT user_no from [PC-ID].[Cash].[dbo].[user_cash]
where free_amount LIKE 0) SET @group_id = (SELECT group_id from
[PC-ID].[Cash].[dbo].[user_cash] where free_amount LIKE 0) SET
@amount = (SELECT amount from [PC-ID].[Cash].[dbo].[user_cash]
where free_amount LIKE 0) SET @free_amount = (SELECT free_amount from
[PC-ID].[Cash].[dbo].[user_cash] where free_amount LIKE 0) SET
@guild_codex = (SELECT guild_code from siege_info where siege_tag LIKE'Y')
SET @character_name0 = (SELECT character_name from guild_char_info
where guild_code LIKE @guild_codex and peerage_code LIKE 0) SET
@user_no0 = (SELECT user_no from user_character where character_name
LIKE @character_name0)
use cash
UPDATE user_cash SET
[email protected]_Leader WHERE user_no = @user_no0
'SELECT TOP 1 * FROM' - 或類似 – 2013-05-13 23:41:30
SQL服務器指責你試圖把多個值到一個簡單,不表,可變碼。你有幾個'SELECT'沒有'WHERE'子句。他們中的任何一個返回多個值? – HABO 2013-05-14 00:03:53
添加了所有where子句,但我仍然得到該錯誤:\ 在最後一部分中,我想爲siege_no coloumn中的所有行設置@user_nox值,其中所有user_no都像user_nox。我該怎麼做? – 2013-05-14 00:18:58