PHP數組計數時，ID和可變匹配

Question

晚上好，

我打破我的頭以下... 我得到多數民衆贊成計算有多少場比賽有像所有其他信息都起到了腳本，點，進球，進球對你..

但我也想知道有多少匹配的球隊都贏得/平局的目標/丟失等

我只是不能似乎得到它。 數據庫中的表，我得到了以下字段名爲

(homePoints, awayPoints, homeResult, awayResult) 
(3,   0,   win,  lose) 

這是我得到返回的數組的一部分：

2 => 
    array (size=7) 
     'TeamID' => string '1' (length=1) 
     'Matches' => string '1' (length=1) 
     'GoalsVoor' => string '2' (length=1) 
     'GoalsTegen' => string '0' (length=1) 
     'DoelSaldo' => int 2 
     'Punten' => string '3' (length=1) 
     'MatchResult' => string 'win' (length=3) 
    3 => 
    array (size=7) 
     'TeamID' => string '1' (length=1) 
     'Matches' => string '2' (length=1) 
     'GoalsVoor' => string '2' (length=1) 
     'GoalsTegen' => string '7' (length=1) 
     'DoelSaldo' => int -5 
     'Punten' => string '0' (length=1) 
     'MatchResult' => string 'lose' (length=4) 

現在，當你看到TeamID是匹配，但MatchResults麥凱納噸，我想或者使一個子陣列像

TeamID => 1 
MatchesWon => 1 and adding if the win more. 
MatchesLost => 1 and adding if they lose more. 
MatchesDraw => 0 and adding if they draw more. 

但不能弄明白。

任何幫助，將不勝感激。

親切的問候， 帕特里克

Answer 1

繼承人我會做什麼

$teams = array(); // Empty array for your teams 
$results = array('wins' => 0, 'draws' => 0, 'losses' = 0); // Starting array for each team 
foreach ($array as $a) { // Loop over your database array 
    $id = $a['TeamID']; // Use TeamID as your array keys 
    if (!isset($teams[$id])) { // Check if team is already in your teams array 
     $teams[$id] = $results; // If not then insert them with the starting array 
    } 
    if ($a['Punten'] == 0) {   // Now loop over the points column and increment results 
     $teams[$id]['losses'] += 1; 
    } 
    if ($a['Punten'] == 1) { 
     $teams[$id]['draws'] += 1; 
    } 
    if ($a['Punten'] == 3) { 
     $teams[$id]['wins'] += 1; 
    } 
}