我有下面的查詢,它是由一個PHP函數生成的,它變得非常複雜,但它迄今爲止工作正常。複雜的字段加入MySQL查詢
我想要做的就是由第二場覆蓋一個場如果第三場等於1
所以我想表2 .cpda_meta_val實際上等於表3 .cpda_meta_val當表4 .cpda_meta_val等於1,這樣我就可以在WHERE/ORDER BY子句中使用結果值table2.cpda_meta_val。
我希望我的理解到目前爲止。
這裏是原始查詢:
SELECT
mainTable.cpda_id
FROM
cp_data AS mainTable
LEFT OUTER JOIN
cp_data AS table0
ON table0.cpda_meta_id = mainTable.cpda_id
AND table0.cpda_meta_key = '47248'
LEFT OUTER JOIN
cp_data AS table1
ON table1.cpda_meta_id = mainTable.cpda_id
AND table1.cpda_meta_key = '47241'
LEFT OUTER JOIN
cp_data AS table2
ON table2.cpda_meta_id = mainTable.cpda_id
AND table2.cpda_meta_key = '47242'
LEFT OUTER JOIN
cp_data AS table3
ON table3.cpda_meta_id = mainTable.cpda_id
AND table3.cpda_meta_key = '66838'
LEFT OUTER JOIN
cp_data AS table4
ON table4.cpda_meta_id = mainTable.cpda_id
AND table4.cpda_meta_key = '66843'
LEFT OUTER JOIN
cp_data AS table5
ON table5.cpda_meta_id = mainTable.cpda_id
AND table5.cpda_meta_key = '47252'
LEFT OUTER JOIN
cp_data AS table6
ON table6.cpda_meta_id = mainTable.cpda_id
AND table6.cpda_meta_key = '47255'
WHERE
mainTable.cpda_meta_id = 47236
AND mainTable.cpda_active = 1
AND mainTable.cpda_meta_key = 'set_element_stub'
AND table0.cpda_meta_val = 49297
AND table1.cpda_meta_val != 66116
AND (
table5.cpda_meta_val = 497
OR table6.cpda_meta_val = 497
)
ORDER BY
table2.cpda_meta_val,
mainTable.cpda_seq,
mainTable.cpda_id
這是我在實現上述,不工作,嘗試檢索沒有行:
SELECT
mainTable.cpda_id
FROM
cp_data AS mainTable
LEFT OUTER JOIN
cp_data AS table0
ON table0.cpda_meta_id = mainTable.cpda_id
AND table0.cpda_meta_key = '47248'
LEFT OUTER JOIN
cp_data AS table1
ON table1.cpda_meta_id = mainTable.cpda_id
AND table1.cpda_meta_key = '47241'
LEFT OUTER JOIN
cp_data AS table2
ON table2.cpda_meta_id = mainTable.cpda_id
AND table2.cpda_meta_key = '47242'
LEFT OUTER JOIN
cp_data AS table3
ON table3.cpda_meta_id = mainTable.cpda_id
AND table3.cpda_meta_key = '66838'
LEFT OUTER JOIN
cp_data AS table4
ON table4.cpda_meta_id = mainTable.cpda_id
AND table4.cpda_meta_key = '66843'
LEFT OUTER JOIN
cp_data AS table5
ON table5.cpda_meta_id = mainTable.cpda_id
AND table5.cpda_meta_key = '47252'
LEFT OUTER JOIN
cp_data AS table6
ON table6.cpda_meta_id = mainTable.cpda_id
AND table6.cpda_meta_key = '47255'
CASE
WHEN table4.cpda_meta_val = 1 THEN table3.cpda_meta_val
ELSE table2.cpda_meta_val
END as table2.cpda_meta_val
WHERE
mainTable.cpda_meta_id = 47236
AND mainTable.cpda_active = 1
AND mainTable.cpda_meta_key = 'set_element_stub'
AND table0.cpda_meta_val = 49297
AND table1.cpda_meta_val != 66116
AND (
table5.cpda_meta_val = 497
OR table6.cpda_meta_val = 497
)
ORDER BY
table2.cpda_meta_val,
mainTable.cpda_seq,
mainTable.cpda_id
如果有人可以點我正確的方向,這將是偉大的!謝謝!
編輯 - 對於那些搜索,我用下面戈登的回答,使下面的查詢,現在的工作:
SELECT
mainTable.cpda_id,
(CASE
WHEN table4.cpda_meta_val = 1 THEN table3.cpda_meta_val
ELSE table2.cpda_meta_val
END) as override_val_0
FROM
cp_data AS mainTable
LEFT OUTER JOIN
cp_data AS table0
ON table0.cpda_meta_id = mainTable.cpda_id
AND table0.cpda_meta_key = '47248'
LEFT OUTER JOIN
cp_data AS table1
ON table1.cpda_meta_id = mainTable.cpda_id
AND table1.cpda_meta_key = '47241'
LEFT OUTER JOIN
cp_data AS table2
ON table2.cpda_meta_id = mainTable.cpda_id
AND table2.cpda_meta_key = '47242'
LEFT OUTER JOIN
cp_data AS table3
ON table3.cpda_meta_id = mainTable.cpda_id
AND table3.cpda_meta_key = '66838'
LEFT OUTER JOIN
cp_data AS table4
ON table4.cpda_meta_id = mainTable.cpda_id
AND table4.cpda_meta_key = '66843'
LEFT OUTER JOIN
cp_data AS table5
ON table5.cpda_meta_id = mainTable.cpda_id
AND table5.cpda_meta_key = '47252'
LEFT OUTER JOIN
cp_data AS table6
ON table6.cpda_meta_id = mainTable.cpda_id
AND table6.cpda_meta_key = '47255'
WHERE
mainTable.cpda_meta_id = 47236
AND mainTable.cpda_active = 1
AND mainTable.cpda_meta_key = 'set_element_stub'
AND table0.cpda_meta_val = 49297
AND table1.cpda_meta_val != 66116
AND (
table5.cpda_meta_val = 497
OR table6.cpda_meta_val = 497
)
ORDER BY
override_val_0,
mainTable.cpda_seq,
mainTable.cpda_id
我認爲第一件事 - 就是將複雜和難以理解的視爲可理解的名稱和含義,可以應用一些覆蓋。然後重寫查詢,只使用必填字段並對其進行最小更改。 – 2014-09-18 15:48:21
我認爲VIEWs對於這種看法來說是過分的,因爲查詢是通過代碼生成的並且基本上是自動的。我現在使用下面的答案作爲發電機弓的另一個可以說。 – bbeckford 2014-09-19 09:18:14