MySQL錯誤＃1064無法找到解決方案？

我意識到錯誤屬於語法 - 我對MySQL相當新;但我通常知道我的方式。這個錯誤一直困擾着我好幾天！任何和所有的幫助，將不勝感激，謝謝！MySQL錯誤＃1064無法找到解決方案？

錯誤：

Connected successfully! SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 USER EXISTS

CODE（我把範圍縮小到這兩個功能，ADDUSER（）調用doesUserExist（））：

function doesUserExist($user, $conn) { 

    try { 

     // Setting the query and runnin it... 
     $sql = "SELECT COUNT(email) FROM userinformation WHERE email = $user"; 
     $result = $conn->query($sql); 

     // If it's greater than 0 then the account exists 
     if ($result != 0) { 
      echo "more than 0"; 
      return true; // user exists 
     } else { 
      echo "0"; 
      return false; // user does not exist 
     } 
    } 
    // Catching it if something went wrong. 
    catch(PDOException $e) { 
     echo $e->getMessage(); 
    } 
} 

function addUser($user, $conn) { 
    echo $user; 
    // If user does not exist 

    if (doesUserExist($user, $conn) === false) { 
     // Add user to database (begin this process) 
     $sqlEntry = "INSERT INTO userinformation (email, password) VALUES('alexnord', 'password')"; 
     $query = $conn->query($sqlEntry); // insert data into table 

    } else { 
     // Take to profile homepage 
     echo "USER EXISTS"; 
    } 
}

來源

2015-12-09 Alex

請使用PHP的[內建函數]（http://jayblanchard.net/proper_password_hashing_with_PHP。 html）來處理密碼安全性。如果您使用的PHP版本低於5.5，則可以使用'password_hash（）'[兼容包]（https://github.com/ircmaxell/password_compat）。 –

你忘記字符串輸入單引號，您的選擇查詢應該是

$sql = "SELECT COUNT(email) FROM userinformation WHERE email = '$user'";

來源

2015-12-09 19:07:19

他可以更新查詢並查看結果 –

MySQL錯誤＃1064無法找到解決方案？

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