選擇行如果列值不一樣以前行

Question

我有一個像下面

No. FName Age Tag 
1 abc 22 c 
2 xyz 60 c 
3 pqr 62 i 
4 abc 22 i 
5 abc 32 i 

我想返回的結果作爲

No. FName Age Tag 
1 abc 22 c 
2 xyz 60 c 
3 pqr 62 i 
5 abc 32 i 

需求是一個表，如果一列NameAND第Age列值與tag=c and tag=i行相同，比tag=i行應該不是被選中。

行號1和行號。 4具有相同的值(Name,age)=(abc,22)，但第4行的tag = i。
因此，排除(abc,22,i)以上的第4行必須排除在外。我怎樣才能做到這一點 ？

Answer 1

WITH records 
AS 
(
    SELECT No, FName, Age, Tag, 
      ROW_NUMBER() OVER (PARTITION BY FName, Age 
           ORDER BY Tag ASC) rn 
    FROM tableName 
    WHERE TAG IN ('c','i') 
) 
SELECT No, FName, Age, Tag 
FROM records 
WHERE rn = 1 

• SQLFiddle Demo

，如果你有TAG其他特殊值，

WITH records 
AS 
(
    SELECT No, FName, Age, Tag, 
      ROW_NUMBER() OVER (PARTITION BY FName, Age 
           ORDER BY CASE WHEN TAG = 'c' THEN 0 ELSE 1 END ASC) rn 
    FROM tableName 
    WHERE TAG IN ('c','i') 
) 
SELECT No, FName, Age, Tag 
FROM records 
WHERE rn = 1 
ORDER BY No 

• SQLFiddle Demo

更新1

SELECT Fname, Age, MIN(tag) Tag 
FROM TableName 
WHERE TAG IN ('c','i') 
GROUP BY Fname, Age 

• SQLFiddle Demo

Answer 2

我想你可以簡單地忽略與tag所有行= '我'，如果已存在一行相同age，name和tag =「C '：

select * from TableName t1 
where not exists 
      (select 1 
      from TableName 
      where FNAme = t1.FNAme and Age = t1.Age and t1.Tag = 'i' and tag = 'c')