PHP，獲得客戶端的IP地址

我有一臺服務器（http://www.xxxx.com/php/）的同一目錄中的兩個PHP文件，PHP，獲得客戶端的IP地址

1）write_json.php

 


    $address['http_client'] = $_SERVER['HTTP_CLIENT_IP']; 
    $address['http_x_forwarded_for'] = $_SERVER['HTTP_X_FORWARDED_FOR']; 
    $address['http_x_forwarded'] = $_SERVER['HTTP_X_FORWARDED']; 
    $address['http_forwarded_for'] = $_SERVER['HTTP_FORWARDED_FOR']; 
    $address['http_forwarded'] = $_SERVER['HTTP_FORWARDED']; 
    $address['remote_addr'] = $_SERVER['REMOTE_ADDR']; 

    header('Content-Type: application/json'); 
    echo json_encode($address);

2）get_ip.php

 
    $json_url = $_SERVER['SERVER_NAME'] . '/php/write_json.php'; 

    $json_string = ''; 
    $ch = curl_init($json_url); 


    $options = array(CURLOPT_RETURNTRANSFER => true, 
         CURLOPT_HTTPHEADER => array('Content-type: application/json'), 
         CURLOPT_POSTFIELDS => $json_string); 

    curl_setopt_array($ch, $options); 

    $json_string = curl_exec($ch); 
    echo $json_string;

get_ip.php 個電話 write_json.php

如果我們假定客戶端IP爲：76.2.35.46和服務器之一是：80.59.3.23
當我打電話http://www.xxxx.com/php/get_ip.php在客戶端瀏覽器

這表明我不是服務器IP客戶端IP是這樣的：

 
{ 
    http_client: null, 
    http_x_forwarded_for: null, 
    http_x_forwarded: null, 
    http_forwarded_for: null, 
    http_forwarded: null, 
    remote_addr: "80.59.3.23" 
}

我怎樣才能獲取客戶端IP而不是服務器？

來源

2013-07-09 user2566349