2
import pandas as pd
def greater_or_less(d):
if d['current'] > d['previous']:
d['result']="Greater"
elif d['current'] < d['previous']:
d['result']="Less"
elif d['current'] == d['previous']:
d['result']="Equal"
else:
pass
return d
df=pd.DataFrame({'current':[1,2,2,8,7]})
# Duplicate the column with shifted values
df['previous']=df['current'].shift(1)
df['result']=""
df=df.apply(greater_or_less,axis=1)
結果是:獲取上一行值適用()函數
current previous result
1 NaN
2 1 Greater
2 2 Equal
8 2 Greater
7 8 Less
我然後刪除previous
列,因爲它是不再需要。結束於:
current result
1
2 Greater
2 Equal
8 Greater
7 Less
如何在不添加額外列的情況下做到這一點?
我想要做的是知道如何從greater_or_less
函數中引用上一行的值。