使用select result in update oracle

Question

我已經搜索並發現了許多類似於我的問題，但沒有一個解決方案適用於我。這是在Oracle中，我不知道版本（我只能通過SQL Developer訪問它）。我有兩個表（略無關列）：

describe t_points_receipt 
Name    Null  Type   
----------------- -------- ------------- 
USER_ID   NOT NULL NUMBER(9)  
PROMOTION_ID  NOT NULL NUMBER(9)  
AMOUNT   NOT NULL NUMBER(9,2) 

describe t_user_promotion_points 
Name   Null  Type   
------------ -------- ----------- 
USER_ID  NOT NULL NUMBER(9) 
PROMOTION_ID NOT NULL NUMBER(9) 
TOTAL_POINTS   NUMBER(9,2) 

而且，我有這個疑問：

select user_id, promotion_id, sum(amount) from t_points_receipt 
where promotion_id = 10340 group by user_id, promotion_id; 

我想這樣做是與結果，其中t_user_promotion_points總和（金額）更新t_user_promotion_points .user_id =（結果）.user_id和t_user_promotion_points.promotion_id =（結果）.promotion_id。有沒有辦法做到這一點？

Answer 1

您可以創建相關子查詢的值設置：

update t_user_promotion_points p 
set total_points = (select sum(amount) from t_points_receipt r where p.user_id = r.user_id and p.promotion_id = r.promotion_id) 
where p.promotion_id = 10340; 

Answer 2

update t_user_promotion_points p 
set total_points = select sum(amount) from t_points_receipt r 
on p.user_id = r.user_id 
where r.promotion_id = 10340 and 
where t.promotion_id = 10340